Assuming we need to find i such that
1 ≤ i ≤ n and t[i]=i.
If we need to find only the first occurrence, we can do:
for i:1 to n {
if t[i]=i then return(i)
}
If exhaustive search is required, then put the results (values of i) in an array or a linked list, return the number of values found, and the array (or linked list).
Answer:
A. SAS B. SSS C. AAS D. ASA
Step-by-step explanation:
A: Line segments AE and EB are congruent and line segments CE and ED are also congruent. The Angles in between line segments AE and EB and line segments CE and ED are congruent to each other
B: Line segments QT and TS are congruent. Line segments QR and RS are congruent. Both triangles share line segment TR
C: Angles A and B are congruent. Angles D1 and D2 are congruent. Line segment CD is shared between both triangles.
D: Angles C1 and C2 are congruent. Angles B1 and B2 are congruent. Line segment CB is shared between the two triangles.
14 to 8
14/8 is going to equal 7/4 you get by doing this :<span> </span>
<span>= (14 ÷ 2)/(8 ÷ 2) </span>
<span>= 7/4 </span>
<span>= 1 3/4</span>
Answer:
Step-by-step explanation:
28 over 60 or 0.46
