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inn [45]
3 years ago
13

Find the Value of X (angles)

Mathematics
2 answers:
STatiana [176]3 years ago
7 0

Answer:

x= 55

Step-by-step explanation:

The  two angles add to 180 degrees since they form a straight line

2x+70 =180

Subtract 70 from each side

2x+70-70=180-70

2x= 110

Divide by 2

2x/2 = 110/2

x= 55

sergeinik [125]3 years ago
3 0

Answer:

x=55°

Step-by-step explanation:

2x+70=180°

x=55°

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2

Step-by-step explanation: divide 4 by 2 its 2!

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Do you have to use substitution? 
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What is 0.08 in 1/10
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1/10 of 0.08 is 0.008
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Three research departments have 9, 7, and 10 members, respectively. Each department is to select a delegate and an alternate to
aivan3 [116]
Work:
First department: (They have 9 possibilities for delegate and 8 for alternate)
9 * 8 = 72
Second department: (They have 7 possibilities for delegate and 6 for alternate)
7 * 6 = 42
Third department: (They have 10 possibilities for delegate and 9 for alternate)
10 * 9 = 90
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I hope this helps!
3 0
3 years ago
The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

3 0
3 years ago
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