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2 years ago

Math Help PLZ!!!!!!!!!

Mathematics

1 answer:

VMariaS [17]2 years ago

4 0

Answer: C

Step-by-step explanation:

f(x) = 2x + 1 ⇒ 2x + 1

- g(x) = -(x² - 7) ⇒ -x² + 7

(f-g)(x) = -x² + 2x + 8

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Solve for g. -6g – 5 + 5 = 2 – 8g

sergey [27]

Answer:

8.875

Step-by-step explanation:

The +5 and -5 cancel, so you are left with -69=2-8g. Subtract two on both sides to get -71=-8g then divide both side by -8 to get g=8.875.

6 0

2 years ago

Read 2 more answers

A deposit of $4,500 at 5% for 3 years:

tekilochka [14]

I = 4500 × 0.05 × 3
I = $ 675.00

7 0

3 years ago

Four students (A, B, C, and D) are interviewing for an all-expenses-paid vacation to a country of their choice. Only one student

Shkiper50 [21]

Answer:

A. 0.36 ; B. 0.72

Step-by-step explanation:

Probability of A, B, C, D to win the interview = P(A), P(B), P(C), P(D)

Given : P(A) = 2 P(B) ∴ P(B) = P(A) / 2

P(B) = 2/3 P(C) ∴ P(C) = 3/2 P(B) ∴ P(C) = 3/2 [P(A) / 2 ]

So, P(C) = 3/4 P(A)

P(C) = 1.5 P(D) ∴ P(C) = 3/2 P(D) ∴ P(D) = 2/3 P(C)

∵ P(C) = 3/4 P(A) ∴ P(D) = 2/3 [3/4 P(A)]

So, P(D) = 1/2 P(A)

Either of them will definitely win the interview. So probability of A or B or C or D winning = 1

So, P(A) + P(B) + P(C) + P(D) = 1

Putting above values : P(A) + P(A) / 2 + 3/4 P(A) + 1/2 P(A) = 1

P(A) [1+ 1/2 + 3/4+ 1/2] = [(4+2+3+2) /4] P(A)

∴ 2.75 P(A) = 1

So, P(A) = 1/2.75 = 0.36

P(B) = P(A)/2 = 0.36 /2 = 0.18

P(C) = 3/4 P(A) = 0.36 (3/4) = 0.27

P(D) = P(A)/2 = 0.36 /2 = 0.18

A. Probability A wins election = 0.36

B. Probability C doesn't win election = Pr A or B or D win election

= Pr (A) + Pr (B) + Pr (D) = 0.36 + 0.18 + 0.18 = 0.72

4 0

2 years ago

2(7/17)+3y=-2. what is the value of y?

Olin [163]

-16/17 is the answer...

2(7/17)+3y=-2
14/17+3y=-2
3y=-2 - 14/17
y = (-2 - 14/17)/3
y = -16/17

8 0

2 years ago

Read 2 more answers

Help with math again *10 pts* asap

Romashka [77]

Answer:

$a_n=2n+5$

Step-by-step explanation:

we have the sequence

$7,9,11,...$

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant and this term is called a common difference

Let

$a_1=7\\a_2=9\\a_3=11$

we know that

$a_2-a_1=9-7=2$ ----> $a_2=a_1+2$

$a_3-a_2=11-9=2$ ----> $a_3=a_2+2$

The common difference is 2

This is an arithmetic sequence

The general formula for an arithmetic sequence is

$a_n=a_1+d(n-1)$

where

d is the common difference

n is the number of terms

substitute the given values

$a_n=7+2(n-1)$

$a_n=7+2n-2$

$a_n=2n+5$

5 0

2 years ago