3 years ago

Math Help PLZ!!!!!!!!!

Mathematics

1 answer:

VMariaS [17]3 years ago

4 0

Answer: C

Step-by-step explanation:

f(x) = 2x + 1 ⇒ 2x + 1

- g(x) = -(x² - 7) ⇒ -x² + 7

(f-g)(x) = -x² + 2x + 8

You might be interested in

Which is the correct first step in finding the height of a cylinder with a volume of 178 cubic inches and a radius of 8 inches?

Strike441 [17]

Answer:

Step-by-step explanation:

Ccc

3 0

3 years ago

I need helppppppppppppp

ohaa [14]

Simplify

4ax+12-3ax=25+3a

ax+12=25+3a

ax-3a=25-12

a(x-3)=13

5 0

3 years ago

If the measure of the base of a triangle is 3b+2 and the height is 4b,represent the area of the triangle

Naily [24]

Answer:

6b^2 +4b

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

A = 1/2 * (3b+2) * (4b)

=1/2 (12 b^2 +8b)

= 6b^2 +4b

3 0

3 years ago

-2|0.25-0.5 |+2= What is this answer

Anestetic [448]

1.5

...

−2∣−0.25∣+2

−2×0.25+2

−0.5+2

8 0

3 years ago

a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig

Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when $h=0$ , this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

$h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5$

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

5 0

3 years ago

Read 2 more answers