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2 years ago

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medical research team is conducting a study to determine whether there is a relationships between aerobic walking and cholestero

l levels. A random sample of 315 subjects is selected and represented in the table below. Test the claim that walking and cholesterol levels are related. Include appropriate statistical evidence to support your findings.

1 answer:

Murrr4er [49]2 years ago

4 0

Answer:

Chi-Square and Linearization ... A random sample of 315 subjects is selected and represented in the table below. ... claim that aerobic walking and cholesterol levels are related.

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Use inverse operations and properties of equality to isolate the variable m+31=307

otez555 [7]

ANSWER

$m = 276$

EXPLANATION

The given equation is

$m + 31 = 307$

We add the additive inverse of 31 which is -31 to both sides of the equation to get,

$m + 31 + - 31= 307 + - 31$

Simplify;

$m +0= 307 - 31$

$m = 276$

6 0

3 years ago

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Rus_ich [418]

For number 9 put the equation in the graphing calculator and see what the outcome is

5 0

3 years ago

A country’s population in 1993 was 94 million.

Wewaii [24]

Answer:

Step-by-step explanation:

A = Pe^rt

A = total

P = amount you start with

r = rate

t = time

Let's calculate the rate.

99000000 = 94000000e^r*6

Divide each side by 94m

99000000/94000000 = e^6r

Take the natural log of e of both sides.

ln(99000000/94000000) = 6r

Divide each side by 6.

(ln(99000000/94000000))/6 = r

Now we can find the population in 2005.

A = 94000000e^0.00863751131 * 12

A = 104265957

The population in 2005 is 104,265,957 people.

6 0

3 years ago

Which of the following equations has a slope of -2 and passes through the point (2,3)?

ryzh [129]

Option C (Same as Option D)

<h2>Explanation:</h2>

Option C and D are the same, so I'll assume you made a mistake when writing this question. However, let's figure out which of the following equations has a slope of -2 and passes through the point (2,3):

A. y = -2x + 6

B. y - 3 = -2(x + 2)

C. y = -2x + 7

<em />

<em>All these equations have a slope of -2.</em>

FROM OPTION A:

$Recall \ our \ point \ is \ (2,3), \ so: \\ \\ x=2 \\ \\ y=3 \\ \\ Substituting \ into \ the \ equation: \\ \\ 3=-2(2)+6 \\ \\ 3=-4+6 \\ \\ 3=2 \ False!$

Since $3\neq 2$ then the line doesn't pass through the point (2, 3)

FROM OPTION B:

$Recall \ our \ point \ is \ (2,3), \ so: \\ \\ x=2 \\ \\ y=3 \\ \\ Substituting \ into \ the \ equation: \\ \\ 3-3=-2((2)+2) \\ \\ 0=-2(4) \\ \\ 0=-8 \ False!$

Since $0\neq -8$ then the line doesn't pass through the point (2, 3)

FROM OPTION C:

$Recall \ our \ point \ is \ (2,3), \ so: \\ \\ x=2 \\ \\ y=3 \\ \\ Substituting \ into \ the \ equation: \\ \\ 3=-2(2)+7 \\ \\ 3=-4+7 \\ \\ 3=3 \ True!$

Since $3\neq 3$ then the line passes through the point (2, 3)

<em>Finally, the equation that has a slope of -2 and passes through the point (2,3) is Option C (Same as Option D)</em>

<em></em>

<h2>Learn more:</h2>

x and y intercepts of a line: brainly.com/question/13770925#

#LearnWithBrainly

5 0

3 years ago

In Exercises 3–10, use the Chain Rule to calculate the partial derivatives. Express the answer in terms of the independent varia

sashaice [31]

I'll use subscript notation for brevity, i.e.

$\dfrac{\partial f}{\partial x}=f_x$

3.

$f(x,y,z)=xy+z^2\implies\begin{cases}f_x=y\\f_y=x\\f_z=2z\end{cases}$

$x(r,s)=s^2\implies\begin{cases}x_r=0\\x_s=2s\end{cases}$

$y(r,s)=2rs\implies\begin{cases}y_r=2s\\y_s=2r\end{cases}$

$z(r,s)=r^2\implies\begin{cases}z_r=2r\\z_s=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=2xs+4zr=2s^3+4r^3$

$f_s=f_xx_s+f_yy_s+f_zz_s=2ys+2xr=6rs^2$

4.

$x(r,s,t)=r+s-2t\implies\begin{cases}x_r=1\\x_s=1\\x_t=-2\end{cases}$

$y(r,s,t)=3rt\implies\begin{cases}y_r=3t\\y_s=0\\y_t=3r\end{cases}$

$z(r,s,t)=s^2\implies\begin{cases}z_r=0\\z_s=2s\\z_t=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=y+3xt=3rt+3r+3s-6t^2$

$f_s=f_xx_s+f_yy_s+f_zz_s=y+4zs=3rt+4s^3$

$f_t=f_xx_t+f_yy_t+f_zz_t=-2y+3xr=3r+3s-12rt$

8 0

2 years ago