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Scrat [10]
2 years ago
5

What is this problem?

times%2010%20%7B%7D%5E%7B3%29%7D%20" id="TexFormula1" title="(4.6 \times 10 {}^{3} ) + (8.72 \times 10 {}^{3)} " alt="(4.6 \times 10 {}^{3} ) + (8.72 \times 10 {}^{3)} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
podryga [215]2 years ago
8 0
The answer would be 13,320
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The population of cats in a rural neighborhood has declined in the last year by roughly 30%. Residents hypothesize that this is
zvonat [6]

Answer:

Orinal number of cats=  171

Step-by-step explanation:

Giving the following information:

Decrease in population= 30%

Current population= 120

<u>To calculate the original number of cats, we need to use the following formula:</u>

Orinal number of cats= current population / (1 - decrease)

Orinal number of cats= 120 / (1 - 0.3)

Orinal number of cats=  171

8 0
2 years ago
PLEASE HELPPP !!! I WILL GIVE BRIGHTEst !!!​
djyliett [7]

Answer :

here

13) 4

14) 3

15) 10

16) 8

17) 8

18) 2

19) 9

20) 9

Step-by-step explanation:

Hope this helps

4 0
3 years ago
Is this less than <br> Greater than<br> Or equal too?
kkurt [141]
The values are equal.

Root 5.76= 2.4

-2.4=-2.4
4 0
2 years ago
I told you people that i would be sending out a series of problems todayy!!
qwelly [4]
Each student would need to raise $27.56
3 0
2 years ago
When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0
3 years ago
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