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3 years ago

Can anyone please help me????

Chemistry

2 answers:

olya-2409 [2.1K]3 years ago

7 0

Answer:

I THINK IT MIGHT BE C

Explanation:

alexdok [17]3 years ago

6 0

Answer:

D. B, A, D, C

Explanation:

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Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.

N76 [4]

Answer:

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

=22.4dm

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

)

⇒1000=−1×2.303×2×273×log(

22.4

)

Explanation:

6 0

3 years ago

You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,

telo118 [61]

Answer:

$\frac{[F^{-}]}{[HF]}$ is larger

Explanation:

$pK_{a}=-logK_{a}$ , where $K_{a}$ is the acid dissociation constant.

For a monoprotic acid e.g. HA, $K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}$ and $\frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}$

So, clearly, higher the $K_{a}$ value , lower will the the $pK_{a}$

In this mixture, at equilibrium, $[H^{+}]$ will be constant.

$K_{a}$ of HF is grater than $K_{a}$ of HCN

Hence, $(\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})$

So, $\frac{[F^{-}]}{[HF]}$ is larger

8 0

4 years ago

How would I draw this? Thank you in advance!<br> (Z)-4-chloro-3-methylhept-2-ene

Savatey [412]

Answer:

In the attached photo.

Explanation:

Hello,

You could find the structure in the attached photo, taking into account that the initial (Z) resembles to the trans arrangement for this alkene.

Best regards.

3 0

3 years ago

E.) MO(NO2)3<br> What’s the name

astraxan [27]

Answer:

Molybdenum Nitrite

Explanation:

Mo => Molybdenum

NO2 => Nitrite

4 0

3 years ago

It is the balance between thermal energy and intermolecular forces that determines the state of matter of any substance at room

ExtremeBDS [4]

Answer:

The correct option is;

2) Thermal energy increases by a factor of R

Explanation:

The equipartition energy theorem states that when molecules are in a state of thermal equilibrium, particles within the system posses equal average energy with each degree of freedom which can be known as energy due to a state of having a particular temperature or thermal energy given by the relation

$E_{th}$ = Kinetic energy of translation + Kinetic energy of rotation + Energy of vibration

For a mono-atomic gas, $E_{th}$ = 3/2·n·R·T

For a diatomic gas, $E_{th}$ = 5/2·n·R·T

For a solid element, $E_{th}$ = 3·n·R·T

Therefore, as the temperature is doubled, the thermal energy increases by a factor of R.

5 0

3 years ago