All categories

3 years ago

How do you get from mL to cm cubed

1 answer:

4 0

Definition: Cubic centimeter. A cubiccentimetre (cm3) is equal to thevolume of a cube with side length of 1 centimetre. It was the base unit ofvolume of the CGS system of units, and is a legitimate SI unit. It is equal to a millilitre (ml).

Convert ml to cm cubed - Conversion of Measurement Units

You might be interested in

Molar mass is used in a conversion factor to calculate ___ and uses the units of ____.

inn [45]

Answer:

The molar mass is used in a conversion factor to calculate the weight of one mole of a given compound and uses the units of grams / mole ____.

Explanation:

Se utilizan los pesos atómicos (Z) de cada componente para calcular la masa de 1 mol de compusto, ejemplo:

H20 (agua)

Masa molar H20 = (Peso atomico H) x 2 + Peso atomico 0 = 1, 007g x2 + 16g = 18 gramos / mol

4 0

3 years ago

An empty vial weighs 55.32 g.

ziro4ka [17]

The answer is: Volume of mercury = 9.63 $cm^3$ .

Density (d) is defined as mass of substance divided by its volume. Thus, if mass and density are known, then Volume can be determined.

What is the formula of volume in terms of density?

Let mass of substance be 'm' and volume be 'V'. Thus, as per the definition of density, it is expressed as-

$d =\frac{m}{V}$

Thus, volume can be expressed as-

$V = \frac{m}{d}$

Now, mass of empty vial= 55.32 g and the mass of (vial+ mercury) = 185.56 g.

Thus, mass of mercury = $185.56\ g- 55.32\g = 130.24\ g$

Thus, mass of mercury = 130.24 g and density of mercury = $13.53\ g/cm^3$ . Its volume is calculated as-

$V =\frac{130.24\ g}{13.53\ g/cm^3} = 9.63\ cm^3$

Hence, volume of mercury = 9.63 $cm^3$ .

To learn more about Density and Volume, visit:

brainly.com/question/1028144

#SPJ4

7 0

2 years ago

Sodium+cloride what is the moleculat mass

lidiya [134]

Answer:

58.44 g/mol

Explanation:

just got done with this unit two weeks ago

3 0

3 years ago

Read 2 more answers

A student performs a titration on 25.0 mL of 0.500M HCL(aq) which is placed in an Erlenmeyer flask. Two drops of indicator are a

Leviafan [203]

Answer:

The unknown NaOH base has a concentration of 0.636M

Explanation:

Step 1: the balanced equation

NaOH + HCl → NaCl + H2O

This means for 1 mole of NaOH consumed there is 1 mole of HCl needed to produce 1 mole of NaCl and 1 mole of H2O

Step 2: Calculate moles of HCl used

Number of moles = Concentration * volume = 0.5M * 25*10^-3 L =0.0125 moles

Step 3: Calculate moles of NaOH

Since the mole ratio for HCl and NaOH is 1:1 this means we have 0.0125 moles of NaOH for 0.0125 moles of HCl

Step 4: Calculate Concentration of the unknown NaOH base

Concentration = Number of moles / Volume

Volume of NaOH = 24.64-5 =19.64 mL = 0.01964 L

Concentration = 0.0125/0.01964 = 0.636 M

The unknown NaOH base has a concentration of 0.636M

8 0

3 years ago

How many molecules are in 7V205?

elixir [45]

Answer:

Calculate the number of moles you have by taking the Mass / molar mass. if you have 1000 grams ; then 1,000 g / 151.001 g/mol = X g moles. Then multiply by Avogadros # = 6.022140857 × 10^23 molecules per g mole. The result is the # of molecules of MnSO4

Explanation: Hope this helps

7 0

3 years ago