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3 years ago

Need help again!! with a similar question

Mathematics

1 answer:

elixir [45]3 years ago

5 0

Answer:

9 gal

Step-by-step explanation:

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Jake and mike took a different number of tests. jake scored 85 points on each test. mike's total score was 15 less than jakes to

Daniel [21]

I am to believe that his score was 70.

since mike scored 15 less than 85 i had suspected it was 70

6 0

3 years ago

For a language test with normally distriuted scores, the mean was 70 and the standard deviation was 10. Approximately what perce

Alborosie

Answer: 84.13%

Step-by-step explanation:

Given : The scores in a a language test with normally distributed.

Mean : $\mu=70$

Standard deviation: $\sigma= 10$

Let x be the random variable that represents the scores of students.

Formula for z-score: $z=\dfrac{x-\mu}{\sigma}$

For x= 60 , we have

$z=\dfrac{60-70}{10}=-1$

The probability f test takers scored a 60 or above :-

$P(x\geq60)=P(\geq-1)=1-P(z$

Hence, the percentage of test takers scored a 60 or above = 84.13%

6 0

4 years ago

Compute: 33 * 32 * 31 * 30 * 3−1 * 3−2 =

mario62 [17]

Answer:

Hello there! I'm Ashlynn I'm always here to help!

___________________________________________

(33 * 32 * 31 * 30 * 3) - (1 * 3) - 2 = 2 946 235

___________________________________________

“Every day may not be good... but there’s something good in every day.”

-Alice Morse Earle

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Good Luck!

- Ashlynn

4 0

3 years ago

If (x+2) Is a factor of x^3-6x^2+kx+10 k=?

Arlecino [84]

The value of k is -11

Further explanation:

Any number being a factor states that the value of expression will be equal to zero at the factor.

Given

$x^3-6x^2+kx+10$

and

x+2 is a factor

x+2 = 0

x=-2

If x=-2 is a factor of given expression then the expression will be zero at x=-2

So.

$(-2)^3-6(-2)^2+k(-2)+10 = 0\\-8-6(4)-2k+10 = 0\\-8-24-2k+10 = 0\\-22-2k=0\\-2k=22\\k = -11$

The value of k is -11

Keywords: Synthetic division, Factorization

Learn more about synthetic division at:

#LearnwithBrainly

7 0

3 years ago

Suppose that a company claims that its air fresheners last 19 days, on average. You take many large samples, and find, each time

spayn [35]

My answer would be B 19

19 days is what they claimed but the sample is outside of the 95% confidence interval so

19 x 95% = 19.95

Below this value, 19.95 is the probable mean number of days that the company's air fresheners last. 15,17, and 19 can be the mean number of days.

3 0

3 years ago

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