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3 years ago

Please show work. Geometry question

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

6 0

Answer:

Angles A and B are complementary and the measure of angle A is twice the measure of angle B. Find the measures of angles A and B

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What is the solution of the following systems of equations? y = 1/2x y = -x -3

SVEN [57.7K]

Answer:

x = -2, y = -1

Step-by-step explanation:

System of Equations

Solve the system:

y = 1/2x

y = -x - 3

Multiplying the first equation by 2:

2y = x

Substituting x in the second equation:

y = -2y - 3

Adding 2y:

3y = -3

y = -3/3

y = -1

And x = 2*(-1) = -2

Solution: x = -2, y = -1

7 0

3 years ago

At a school, 147 147 students play at least one sport. This is 35 35% of the students at the school. How many students are at

dsp73

Answer:

420

Step-by-step explanation:

Assuming this is the problem:

At a school, 147 students play at least one sport. This is 35% of the students at the school. How many students are at the school?

147/35 = x/100

35x=147*100

35x=14,700

x=420

3 0

3 years ago

URGENT Perform the indicated operation and simplify the result.

yan [13]

Answer:

The answer to your question is: (2a - 1) / 4

Step-by-step explanation:

$\frac{12a^{2} - 3}{2} (2a + 1)^{-2} ( \frac{6}{(2a +1)^{-1} } \\$

$\frac{3(4a^{2} -1)}{2} \frac{1}{(2z + 1)^{2} } (\frac{2a + 1)}{6}$

$\frac{3(2a + 1)(2a- 1) (2a + 1)}{12(2a + 1)(2a + 1)}$

$\frac{(2a - 1)}{4}$

8 0

3 years ago

10 points?...1) must be quick to answer,2) must be reasonable answer,3) Show explanation for your answer

Ilia_Sergeevich [38]

Your answer is
${x}^{2} \div {2} {z}^{9}$
because the numbers raised to negative powers must be flipped over the divisor to become positive. Then, when multiplying 2 and z, you add their exponents.

3 0

3 years ago

Two cars start out together from the same place. they travel in opposite directions, with one of them traveling 5 miles per hou

Mashutka [201]

Annotation
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.

One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5 (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
$\boxed{\boxed{ v_{1}=68mph} }$
$\boxed{\boxed{ v_{2}=63mph} }$

7 0

4 years ago