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olasank [31]
3 years ago
6

Plzzzz answer the two questions it asks!!!

Mathematics
1 answer:
hammer [34]3 years ago
5 0
Perimeter is 10x^2 y + 6y^3
Area is 15x^2 y^3
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6(w – 2) + 2 = 2(3w - 5)
galben [10]

Answer:

Infinite Solutions

Step-by-step explanation:

7 0
3 years ago
A polygon with side lengths of 6, 9, and 15 forms a triangle. <br> True <br> False
Butoxors [25]

Try this: Combine 6 and 9, obtaining 15.

Compare this sum, 15, to the length of the 3rd side: 15.


If placed end to end, the 2 sides with lengths 6 and 9 form a new line of length 15. We'd end up with this new line superimposed on the 3rd side (with length 15).


Think: Do 2 straight lines of length 15, superimposed on one another, form a triangle?


3 0
4 years ago
Read 2 more answers
A seamstress has 1/4 of a foot of thread.Then she uses 1/5 of a foot of thread to sew a hole How much of the thread is left?
Whitepunk [10]
1/10 of the thread is left because a connected to b is the thread and minus the 1/5 is 1/10 since 1/3 +total thread to begin wit.
3 0
3 years ago
Read 2 more answers
Please help! I will mark brainliest.
jek_recluse [69]

Answer:

the correct answer is D 175

7 0
3 years ago
A fence is to be built to enclose a rectangular area of 320 square feet. The fence along three sides is to be made of material t
sergeinik [125]

The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft

<h3>How to maximize area?</h3>

Let the length of the rectangular area be x feet

Let the width of the area = y feet

Area of the rectangle = xy square feet

Or xy = 320 square feet

y = 320/x  -----(1)

Cost to fence the three sides = $6 per foot

Therefore cost to fence one length and two width of the rectangular area

= 6(x + 2y)

Similarly cost to fence the fourth side = $13 per foot

So, the cost of the remaining length = 13x

Total cost to fence = 6(x + 2y) + 13x

Cost (C) = 6(x + 2y) + 13x

C = 6x + 12y + 13x

C  = 19x + 12y

From equation (1),

C = 19x + 12(320/x)

C' = 19 - 3840/x²

At C' = 0, we have;

19 - 3840/x² = 0

19 = 3840/x²

19x² = 3840

x² = 3840/19

x = √(3840/19)

x = 14.22 ft

y = 320/14.22

y = 22.5 ft

Read more about Maximization of Area at; brainly.com/question/13869651

#SPJ1

8 0
2 years ago
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