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2 years ago

Where does the graph of y = –3x – 18 intersect the x-axis?

Mathematics

1 answer:

Naya [18.7K]2 years ago

5 0

Answer:

b) (-6, 0)

Step-by-step explanation:

The quickest method to use is to put "0" in for y, then figure out which term for x would make the equation authentic, or genuine.

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CAN SOMEONE HELP WITH THIS ASAP!!!

jek_recluse [69]

Answer: x=8

Step-by-step explanation:

Since we are given that ∠ABC and ∠DBC are complementary angles, we know that adding them together should give us 90°. We can use this to solve for x.

6x+13+4x-3=90 [combine like terms]

10x+10=90 [subtract both sides by 10]

10x=80 [divide both sides by 10]

x=8

Now, we know that x=8.

6 0

3 years ago

Am I right? I want to know if I am right

german

Answer:

B $13

Step-by-step explanation:

Julie has 16.73 That is approximately 17 dollars

She buys a purse that is 4.12. That is approximately 4 dollars

17 -4 = 13

She will have approximately 13 dollars left

8 0

2 years ago

Read 2 more answers

HELP ME!!! I wanna pass please

ale4655 [162]

The answer would be c (w = 12 feet)!

5 0

2 years ago

Read 2 more answers

Find the point at which the line joining the two points (-3,-5) and (7,5) cuts they y axis

8090 [49]

Answer:

(0,-2)

Step-by-step explanation:

First we find the equation of the line passes through $(-3,-5)$ and $(7,5)$ .

The slope of the line is

$m=\frac{5-(-5)}{7-(-3)}\\=\frac{10}{10}\\=1$

So by the point slope formula the equation of the line is

$y-5=1(x-7)\\y=x-7+5\\y=x-2$

When $x=0$ we have $y=0-2=-2$ .

Therefore the line joining the two points cuts the y-axis at (0,-2).

4 0

2 years ago

A backyard pool has a concrete walkway around it that is 3 feet wide on all sides. The total area of the pool and the walkway is

Gnoma [55]

Answer:

<h2>29.4 length and 21.4 width.</h2>

Step-by-step explanation:

To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that W is the width and L the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this: $A_{total} = (L+6)(W+6)$ .

In addition, we know that the total area is 970 and the length is 8 ft longer than the width ( $L=W+8$ ). So:

$A_{total} = (L+6)(W+6)\\970 = (W+8+6)(W+6)\\970=W^{2}+20W+84\\W^{2}+20W-886=0$

With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions: $W_{1}=21.4$ and $W_{2}=-41.4$

Therefore, the width is 21.4 ft, because the negative number cannot represent distances.

Using the relation between length and width:

$L=W+8\\L=21.4+8=29.4$

Therefore, the dimensions of the pool are 29.4 length and 21.4 width.

7 0

3 years ago