All categories

2 years ago

There are 10 bananas. Seven of the bananas are ripe. What fraction of the bananas are not ripe?

Mathematics

1 answer:

slega [8]2 years ago

4 0

The answer is 3/10.

Im sure.

You might be interested in

Mr.Rivas bought a can of paint. He used 3/8 of it to paint a bookshelf.He used 1/4 of it to paint a wagon. He used some of it to

Galina-37 [17]

Mr.Rivas used 2/8 of paint for the birdhouse

8 0

3 years ago

To skate at Roller Heaven, each person must pay a membership fee (m) and a fee for each session (f). Art attended five sessions

cestrela7 [59]

M + 5f = 25....multiply by -1
m + 10f = 40
----------------
-m - 5f = -25 (result of multiplying by -1)
m + 10f = 40
-----------------add
5f = 15
f = 3

m + 10f = 40
m + 10(3) = 40
m + 30 = 40
m = 40 - 30
m = 10

so the membership fee (m) = 10 and the sessions(f) = 3

5 0

3 years ago

A cylinder has a height of 4 inches greater than the radius of its base. Find the radius and the height to the nearest inch if t

anastassius [24]

Answer:

$h=5in, r=1in$

Step-by-step explanation:

The volume of a cylinder is:

$V=\pi*r^2*h$

where $r$ is the radius and $h$ is the height.

The height is 4 inches greater that the radius, so:

$h=r+4in$

Substituting this in the formula for volume:

$V=\pi*r^2*(r+4)$

the volume is $V=5\pi in^3$

thus:

$5\pi in^3=\pi*r^2*(r+4in)$

Dividing everything between pi:

$5in^3=r^2*(r+4in)$

$5in^3=r^3*+4r^2$

We can see that the solution for this is $r=1in$

since $(1)^3*+4(1)^2=1+4=5$

We have the radius, now we find the height:

$h=r+4in=1in + 4in = 5in$

$h=5in, r=1in$

7 0

3 years ago

Read 2 more answers

ANYONE HELP PLS THIS IS HARD PLSSS

juin [17]

Answer:

90% sure it's the third option

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the area of a 45 degree sector of a circle with a radius of 12 in.

Elodia [21]

given ,

a circle of radius 12 inches

and $\theta$ = 45°

now we know that ,

$\\{Area \: of \: sector = \frac{\theta}{360\degree} \times \pi \: r {}^{2} } \\ \\$

let's now plug in the values of radius and theta as 12 inches and 45° respectively ,

$\\\dashrightarrow \: \frac{45}{360} \times \frac{22}{7} \times 12 \times 12 \\ \\ \dashrightarrow \: \frac{1}{8} \times \frac{22 \times 12 \times 12}{7} \\ \\ \dashrightarrow \: \frac{22 \times 12 \times 12}{56} \\ \\ \dashrightarrow \: \frac{3168}{56} \\ \\ \dashrightarrow \: 56.57 \: inches {}^{2} (approx.)$

hope helpful :D

6 0

2 years ago