Let x be the unknown number
2x +7 = 39
2x+7-7 = 39-7
2x = 32
2x/2 = 32/2
x=16
You use the balance method to solve. First, you cancel the +7 by subtracting the 7 ON BOTH SIDES to balance the equation.. After that, you are left with 2x, where you will need to isolate the x by dividing by 2 ON BOTH SIDES to balance it.
Hope this helps
Answer:
y = 8/5x
Step-by-step explanation:
I'm assuming that they're asking for the equation in point-slope form.
The formula is y=mx+b where:
m = slope
b = y intercept
However, the y intercept is just (0,0) so b = 0
To find the slope we already have 2 given points: (0,0) and (5,8)
To find slope you do rise/run and you get 8/5
Substitute the slope & y intercept in the formula:
y = 8/5x
Let me know if I'm wrong!!
Answer:
6°F
58°F
Step-by-step explanation:
From the data Given :
Temperature rise in Buffalo by noon time = 14°F
The initial temperature at Buffalo = - 8°F
Rise in temperature = 14°F
Therefore, temperature at noon = (-8 + 14)°F = 6°F
B.)
Temperature at 6am in St. Louis = 32°F
Temperature at 6am in Juneau = - 26°F
Temperature difference :
(32 - (-26))°F
32 + 26
= 58°F
Temperature in St. Louis is 58°F higher
Standard form for the equation of the line is

Solution:
Given point is (2, –5).
slope of the line m = 
Here, 
Equation of a line passing through the point:




Subtract 15 from both sides of the equation.


Standard form for the equation of the line is

Answer:
<em>15.4 </em>
Step-by-step explanation:
= tan51.3° ⇒ u = 4tan51.3° ≈ 5
= cos51.3° ⇒ v =
≈ 6.4
<em>P </em>≈ 4 + 5 + 6.4 = <em>15.4</em>