Answer
We don't know what the inequalities were, so show us 1-4
Step-by-step explanation:
Answer:
1.66666666667
Step-by-step explanation:
Let's set up an equation:
x plus y is greater than 12
x + y > 12
One of the integers is ten less than twice the other one
x = 2y -10
Time to start solving:
(2y-10) + y > 12
2y + y > 12 + 10
3y > 22
3y=24
y=8
Now its time to find the value of x:
x=2(8) - 10
x=16-10
x= 6
6 + 8 > 12, 6+8 is greater than twelve.
In conclusion we can wrap up that 6 and 8 are the least value integers.
Answer:
The range is y ≥ -1
Step-by-step explanation:
∵ f(x) = (x - 4)(x - 2)
∴ f(x) = x² - 2x - 4x + 8
∴ f(x) = x² - 6x + 8 ⇒ quadratic function (ax² + bx + c) represented by
parabola graphically
∵ a = 1 , b = -6 , c = 8
∴ x-coordinate of its vertex = -b/2a = -(-6)/2×1 = 3
∴ f(3) = (3)² - 6(3) + 8 = -1
∵ a is positive ⇒ the curve has minimum point and it's open upward
∴ the minimum point is (3 , -1)
∴ The range is y ≥ -1 ⇒ because the minimum value is -1