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meriva
3 years ago
13

Line segment TV is a midsegment of ∆QRS. What is the value of n in the triangle pictured?

Mathematics
1 answer:
Elis [28]3 years ago
4 0

Answer:

D. 3.2

Step-by-step explanation:

Mid-segment Theorem of a triangle states that the Mid-segment in a triangle is half of the third side of the triangle.

Based on this theorem, we have: TV = ½(RS)

TV = 3n - 2

RS = n + 12

Substitute

3n - 2 = ½(n + 12)

Multiply both sides by 2

2(3n - 2) = (n + 12)

6n - 4 = n + 12

Collect like terms

6n - n = 4 + 12

5n = 16

Divide both sides by 5

5n/5 = 16/5

n = 3.2

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yan [13]

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Terminating means to add. Repeating goes on forever and ever and ever.

Step-by-step explanation:

Example of terminating: 3.256

Example of repeating: 3.256934103...

A good repeating decimal would be pi.

7 0
3 years ago
What is the range of possible values for x?
Talja [164]
The minimum value for 2x is 0 
<span>the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC </span>
<span>base AB = 52 and vertical angle 2x + 34° </span>

<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
<span>(sin 34°)/30 = (sin BDC)/BC </span>

<span>is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from </span>
<span>(sin ADC)/AB = (sin BDC)/BC </span>

<span>it follows </span>
<span>(sin 2x)/22 = (sin 34°)/30 </span>

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<span>2x = asin(22 (sin 34°)/30) ≈ 24.2° </span>

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7 0
3 years ago
How can you write a fraction as a decimal?
Sedbober [7]
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3 0
2 years ago
Which of the following could Not be the side length of a right triangle?
ArbitrLikvidat [17]

Answer:

I think ITS B

Step-by-step explanation:

Hope this helped

-BB

8 0
2 years ago
Read 2 more answers
Kindly answer this one. Thank you.​
steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.

♦  The midline's length is the average of the lengths of the top and bottom parallel sides.

AL=\frac{OR+CE}{2}

Use this equation and substitute values given in each problem, then solve for the missing information.

1. AL = x, CE = 9, OR = 5

x=\frac{9+5}{2}=7

2. AL = <em>m</em> - 4, CE = 15, OR = 17

m-4=\frac{15+17}{2}=16\\\\m-4=16\\\\\\m=20\\\\AL=20-4=16

3. OR = y + 5, AL = 15, CE = 18

15=\frac{(y+5)+18}{2}\\\\15=\frac{y+23}{2}\\\\30=y+23\\\\7=y\\\\OR = 7+5=12

4 0
2 years ago
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