Select the statement that can be represented by -10 dollars.

Math, area all that yummy stuff

lilavasa [31]

Answer:

If im not wrong, just multiply wxlxh, for all sides, and you get 1260.

Step-by-step explanation:

5 0

2 years ago

What are the next three terms in the pattern 2, 6, 18, 54, ...?

castortr0y [4]

Answer:

OPTION B: 162, 486, 1458

Step-by-step explanation:

The given sequence is 2, 6, 18, 54, . . .

It is a geometric sequence and the common difference is 3.

The general form of a geometric sequence is: a, ar, ar², ar³, . . .

Here a = 2 and r = 3.

$n^{th}$ term of a Geometric progression is $ar^{n - 1}$ .

Note that the fourth term is 54.

i.e., $ar^3 = 54$

$\implies ar^4 = ar^3 . r = 54 . 3 = 162$ .

Similarly, $ar^6 = 162 \times 3 = 486$ .

Also, $ar^7 = ar^6 . r = 486 \times 3 = 1458$ .

Hence, OPTION B is the answer.

8 0

3 years ago

Read 2 more answers

25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of

sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

$P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028$

b) Probability that exactly 2 has only cats (p=0.15)

$P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759$

c) Probability that exactly 1 has cats and dogs (p=0.1)

$P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742$

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

$P(x=4)=\binom{10}{4}0.50^40.50^6=210*0.0625*0.01563=0.20508$

8 0

3 years ago

What set of reflections would carry hexagon ABCDEF onto itself?

Marianna [84]

When a set of reflections that carry a shape onto itself, it means that the final position of the shape will be the same as its original location

Reflections (a) y=x, x-axis, y=x, y-axis would carry the hexagon onto itself

First; we test the given options, until we get the true option

(a) y=x, x-axis, y=x, y-axis

The rule of reflection y =x is:

$(x,y) \to (y,x)$

The rule of reflection across the x-axis is:

$(x,y) \to (x,-y)$

So, we have:

$(y,x) \to (y,-x)$

The rule of reflection y =x is:

$(x,y) \to (y,x)$

So, we have:

$(y,-x) \to (-x,y)$

Lastly, the reflection across the y-axis is:

$(x,y) \to (-x,y)$

So, we have:

$(-x,y) \to (x,y)$

So, the overall transformation is:

$(x,y) \to (x,y)$

Notice that, the original and final coordinates are the same.

This means that:

Reflections (a) y=x, x-axis, y=x, y-axis would carry the hexagon onto itself