There are four numbers of 3-coin combinations if we can choose from nickels, dimes, quarters, and half-dollars.
<h3>How to solve probability combinations?</h3>
The coins to select from are nickels, dimes, quarters, and half-dollars;
Thus;
Coins (n) = 4
The number of coin to select is:
Coin (r) = 3
The coin combination is then calculated using:
Combination = ⁴C₃
Apply the combination formula, we have;
Combination = 4
Thus, there are four number 3-coin combinations if we can choose from nickels, dimes, quarters, and half-dollars.
Read more about combinations at; brainly.com/question/4658834
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Answer:
11.6
Step-by-step explanation:
Add all numbers together and divide by 7.
Answer:
The baseball mitt was $37 and the ball was $7
Step-by-step explanation:
Let m represent the cost of the mitt and let b represent the cost of the ball
Set up a system of equations:
m + b = 44
m = 5b + 2
Solve by substitution by plugging in 5b + 2 as m in the first equation:
5b + 2 + b = 44
Solve for b:
6b + 2 = 44
6b = 42
b = 7
Plug in 7 into the first equation and solve for m:
m + b = 44
m + 7 = 44
m = 37
So, the baseball mitt was $37 and the ball was $7
Lets solve your equation step by step:
(x+18)^1/2+2=x
step 1:Add -2 to both sides:
(x+18)^1/2+2-2=x+-2
(x+18^)1/2=x-2
step 2:solve exponent
(x+18)^1/2=x-2
((x+18)^1/2)^2=(x-2)^2
x+18=x^2-4x+4
x+18-(x^2-4x+4)=x^2-4x+4-(x^2-4x+4) (subtract x^2-4x+4 from both sides)
-x^2+5x+14=0
(-x-2)(x-7)=0(factor left side of equation)
-x-2=0 or x-7=0 (set factors equal to zero)
x=-2 or x=7
check answers:(plug them in to make sure they work )
x=-2(doesn't work in original equation)
x=7(works in original equation)
I think that is the answer
