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Ulleksa [173]
2 years ago
15

Easy questions just a bit of help no rush 100 points to do this

Mathematics
1 answer:
Inessa05 [86]2 years ago
6 0

Is this a test or do you need help

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24 hurry is that one in my but
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3 years ago
What is the equation of the line?
svetlana [45]

Answer:

y = -7

Step-by-step explanation:

This line is a horizontal line [HOY] - horizontal, 0 slope, and the equation starts with y = ___ , since it crosses at -7, then the line is y = -7

3 0
3 years ago
A small radio transmitter broadcasts in a 69 mile radius. If you drive along a straight line from a city 93 miles north of the t
larisa86 [58]

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

  • We have A small radio transmitter that broadcasts in a 69-mile radius. If you drive along a straight line from a city 93 miles north of the transmitter to a second city 78 miles east of the transmitter.

Thus,

The distance that you get reception is the length of the chord created by the intersection of the circle defining the edge of transmission and the line defining the car trip.

  •  x2 + y2 = 69²               this is the circle

And,

The Transmitter at the origin

City to the north at (0,93)  & City to the east at (78,0)  

the Slope is M=(-93/78)

Intercept is B= y - mx ⇒  93 - (-93/78)(0) = 93

The equation of the line between the cities is y = (-93/78)x + 93

  • y = -93x/78 + 93           this is the line

Now, Solve the above two Equations

The intersection is gotten from the picture or solving:

x^2 + [(-93/78)*x + 93]^2 = 69^2

  • on solving we get, the points approximately are: (67.952,11.98 ) and (23.6277, 64.82)

Now,

From the Pythagorean theorem the total distance of the trip is:  

d1 = √(93^2 + 78^2) ≈ 121.37miles  

And the distance when the signal is picked up is:

d2 =√ [(67.952-23.627)^2 + (64.82 - 11.98)^2] ≈ 68.96 miles

You will pick up a signal from the transmitter in (d2/d1)*100 = 56% of the drive.

3 0
3 years ago
The point (-3,4) is reflected across the x-axis. What is the coordinates of its new location?
Tasya [4]

Semd a pic of a graph bc I dont have paper

4 0
3 years ago
Find the limit of (lnx)³/x as x approaches infinity.
EastWind [94]
Ok, so one way is like your way

so
if we test some numbers
for x=10
we get about 12.3/10≈1.2
for x=100000
we get 1522.03/100000≈0.01522
the top number keeps getting smaller reletive to bottom number
when x=1000000000
we get 8899.68/1000000000≈0.000009

we notice the bottom number is increaseing at a faster rate that the botom one
when x approaches infinity,the bottom number will be so big it will become a fraction that evaluates to basically zero becuase it evaluates to a very small number that is negligible
5 0
2 years ago
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