Answer:
well, as long as there are no right or wrong answers, don't:
look to closely at the screen, as it may mess up your eyes
hold a drink above the computer, as it may spill and cause "sticky keys"
go to sites that you know will give your a computer a virus, cause they cost hundreds of dollars to repair, and some aren't able to come out
go on illegal sites/do illegal operations to the computer itself, because then you won't have a computer
Explanation:
Answer:
Choose Start > Control Panel > Appearance and Personalization > Personalization. Right-click an empty area of the desktop and choose Personalize. Select a theme in the list as a starting point for creating a new one. Choose the desired settings for Desktop Background, Window Color, Sounds, and Screen Saver
Explanation:
Since no answer choices, have to deduce it is Private Networks
Answer:
- def getCharacterForward(char, key):
- charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
-
- if(len(char) > 1):
- return None
- elif(not isinstance(key, int)):
- return -1
- else:
- index = charList.find(char)
- if(index + key <= 25):
- return charList[index + key]
- else:
- return charList[(index + key)% 26]
-
- print(getCharacterForward("C", 4))
- print(getCharacterForward("X", 4))
Explanation:
Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.
Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).
Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).
However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).
We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:
G
B
Go to the me colum when you first open the app
