Var name = prompt("Enter the name to print on your tee-shirt");

Here is some pseudocode that uses object-oriented programming:

MrRa [10]

Answer:

Explanation:

Using the code snippet in the question, each of the following terms would be considered the...

AlcoholicIngredient = Class Name

Ingredient = Parent Class

volume = member variable, field, or property

calc_total_alcohol = method

ingredient = object

ingredient.input = method call

These would be the classification of each of these terms in the snippet of Object-Oriented Programming Code. The terms after the keyword Class is the Class Name. The term after the keyword extends is the Parent Class. The term volume comes after the keyword Real meaning its an integer variable. cacl_total_alcohol comes after the Public Function keyword making it a method. The variable ingredient comes after the Ingredient Class Name and is being equalled to an ingredient constructor making it an object of class Ingredient. Lastly, the ingredient.input() is calling the input method that exists within the Ingredient class.

4 0

3 years ago

The ____ operator executes one of two expressions based on the results of a conditional expression. Group of answer choices

Mars2501 [29]

Corrected or Complet Question

The ____ operator executes one of two expressions based on the results of a conditional expression.

a. .

b. ( )

c. ,

d. ?:

Answer:

(d) ? :

Explanation:

The ternary operator (? :) is an operator that executes one out of two expressions based on the results of a conditional expression. It is a faster or shorthand way of writing an if ... else statement. The operator checks the conditional expression and depending on whether it is true or false, one of its two statements will be executed. For example:

String correct = (4 < 5) ? "yes" : "no" ;

In the code above,

i. the conditional statement is (4 < 5) and this will be tested for to return true or false.

ii. the first expression (the one after the ?) is "yes" which will be executed if the conditional statement returns true.

iii. and the second expression (the one after the : ) is "no" which will be executed if the conditional statement returns false.

Therefore, since the conditional expression returns true for 4 < 5, the first expression will be executed. i.e "yes". This means that the String variable <em>correct </em> will have a value of "yes".

8 0

3 years ago

Read 2 more answers

Lists and Procedures Pseudocode Practice For each situation, provide a pseudocoded algorithm that would accomplish the task. Mak

Andrei [34K]

Answer:

The pseudocoded algorithm is as follows:

Procedure sumOdd(lotsOfNumbers):

oddSum = 0

len = length(lotsOfNumbers)

for i = 0 to len - 1

if lotsOfNumbers[i] Mod 2 != 0:

OddSum = OddSum + lotsOfNumbers[i]

Print(OddSum)

Explanation:

This defines the procedure

Procedure sumOdd(lotsOfNumbers):

This initializes the oddSum to 0

oddSum = 0

This calculates the length of the list

len = length(lotsOfNumbers)

This iterates through the list

for i = 0 to len-1

This checks if current list item is odd

if lotsOfNumbers[i] Mod 2 != 0:

If yes, the number is added to OddSum

OddSum = OddSum + lotsOfNumbers[i]

This prints the calculated sum

Print(OddSum)

6 0

3 years ago

The running time of Algorithm A is (1/4) n2+ 1300, and the running time of another Algorithm B for solving the same problem is 1

Mnenie [13.5K]

Answer:

Answer is explained below

Explanation:

The running time is measured in terms of complexity classes generally expressed in an upper bound notation called the big-Oh ( "O" ) notation. We need to find the upper bound to the running time of both the algorithms and then we may compare the worst case complexities, it is also important to note that the complexity analysis holds true (and valid) for large input sizes, so, for inputs with smaller sizes, an algorithm with higher complexity class may outperform the one with lower complexity class i.e, efficiency of an algorithm may vary in cases where input sizes are smaller & more efficient algorithm might be outperformed by the lesser efficient algorithms in those cases.

That's the reason why we consider inputs of larger sizes when comparing the complexity classes of the respective algorithms under consideration.

Now coming to our question for algorithm A, we have,

let F(n) = 1/4x² + 1300

So, we can tell the upper bound to the function O(F(x)) = g(x) = x2

Also for algorithm B, we have,

let F(x) = 112x - 8

So, we can tell the upper bound to the function O(F(x)) = g(x) = x

Clearly, algorithmic complexity of algorithm A > algorithmic complexity of algorithm B

Hence we can say that for sufficiently large inputs , algorithm B will be a better choice.

Now to find the exact location of the graph in which algorithmic complexity for algorithm B becomes lesser than

algorithm A.

We need to find the intersection point of the given two equations by solving them:

We have the 2 equations as follows:

y = F(x) = 1/4x² + 1300 __(1)

y = F(X) = 112x - 8 __(2)

Let's put the value of from (2) in (1)

=> 112x - 8 = 1/4x² + 1300

=> 112x - 0.25x² = 1308

=> 0.25x² - 112x + 1308 = 0

Solving, we have

=> x = (112 ± 106) / 0.5

=> x = 436, 12

We can obtain the value for y by putting x in any of the equation:

At x=12 , y= 1336

At x = 436 , y = 48824

So we have two intersections at point (12,1336) & (436, 48824)

So before first intersection, the

Function F(x) = 112x - 8 takes lower value before x=12

& F(x) = 1/4x² + 1300 takes lower value between (12, 436)

& F(x) = 112x - 8 again takes lower value after (436,∞)

Hence,

We should choose Algorithm B for input sizes lesser than 12

& Algorithm A for input sizes between (12,436)

& Algorithm B for input sizes greater than (436,∞)

8 0

3 years ago

Which type of word processing programs enables us to include illustrations within the program?

bonufazy [111]

Answer:

C. full featured

Explanation:

You need to make use of the full-featured version of the word processing programs to use the illustrations that are part of the program. And simple versions might not have that. By fully featured it means you need to have the license included or else you will be able to use it for a few days or a maximum of 3 months, and that is certainly not a good idea.

5 0

3 years ago