Answer:
def feet_to_inches( feet ):
inches = feet * 12
print(inches, "inches")
feet_to_inches(10)
Explanation:
The code is written in python. The unit for conversion base on your question is that 1 ft = 12 inches. Therefore,
def feet_to_inches( feet ):
This code we define a function and pass the argument as feet which is the length in ft that is required when we call the function.
inches = feet * 12
Here the length in ft is been converted to inches by multiplying by 12.
print(inches, "inches")
Here we print the value in inches .
feet_to_inches(10)
Here we call the function and pass the argument in feet to be converted
A large network of networks
<h3>
What Is a large network?</h3>
- It is the biggest network that connects computers across the world. With the internet, people can share data and files over the internet. The Internet is defined as a network of networks Hence it is the correct option
To learn more about the network, refer
to https://brainly.in/question/32165678
#SPJ4
Answer:
An advantage to Corporations aI's a business organization is that they enjoy unlimited life and limited liability.
Explanation:
Unlimited life and limited liability are the major advantages of corporations.
Corporations have unlimited life unless all the shareholders decides to dissolve the corporation.
It has limited liability, it means that only the company assets will be sold in case of debt and investors are not liable to pay the debt.
Answer:
Sequence of popped values: h,s,f.
State of stack (from top to bottom): m, d
Explanation:
Assuming that stack is initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:
push(d) -> enters d to the Stack
Stack:
d ->top
push(h) -> enters h to the Stack
Stack:
h ->top
d ->bottom
pop() -> removes h from the Stack:
Stack:
d ->top
p: Suppose p contains popped values so first popped value entered to p is h
p = h
push(f) -> enters f to the Stack
Stack:
f ->top
d ->bottom
push(s) -> enters s to the Stack
Stack:
s ->top
f
d ->bottom
pop() -> removes s from the Stack:
Stack:
f ->top
d -> bottom
p = h, s
pop() -> removes f from the Stack:
Stack:
d ->top
p = h, s, f
push(m) -> enters m to the Stack:
Stack:
m ->top
d ->bottom
So looking at p the sequence of popped values is:
h, s, f
the final state of the stack:
m, d
end that is the top of the stack:
m