1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Temka [501]
3 years ago
11

At this rate, how much would 6 bagels cost?

Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0

Answer:

2 ½ dollars

Step-by-step explanation:

You take half of 5 and that makes 2 ½

You might be interested in
I need help. Thanks so much
ira [324]

LlL-=2-3=2=3-2=94308500496-405=4

4 0
2 years ago
The first side of a triangle is twice the length of the second side; the third side is 20 feet less than three times the second
oee [108]
Let the second side be x

then,
first side = twice the length of the second side
= 2x

third side = 20 feet less than three times the second side
3 (second side ) - 20
= 3 (2x) -20
= 6x - 20

perimete of a triangle = sum of all sides,

substitute the values we know,
and you'll be left with this equation

106 = x + 2x + 6x - 20
106+ 20 = 9x
126 = 9x
126/9 = x
14 = x

so,

measure of second side = x = 14 feet

measure of first side = 2x = 2 (14) = 28 feet

measure of thurd side = 6x - 20 = 6 (14)-20 = 84- 20 = 64 feet.
4 0
3 years ago
HURRYYY
Dahasolnce [82]
Jack invested 57
Sam invested 38
57 over 38 minus 1,00
7 0
2 years ago
Please help me find the area of this shape
Alex

Answer:

44+50 =94 in²

Step-by-step explanation:

Trapezoid

A= 1/2h(b1+b2)

A= 1/2*4(7+15)

A=1/2*4(22)

A=44

Rectangle

A=l*w

A=5*10

A=50

44+50 =94 in²

3 0
3 years ago
Read 2 more answers
Suppose that a password for a computer system must have at least 8, but no more than 12, characters, where each character in the
uranmaximum [27]

Part a)

There are 52 letters (26 lowercase and 26 uppercase), 10 digits, and 6 symbols. There are 52+10+6 = 68 different characters to choose from.

  • If there are 8 characters for this password, then we have 68^8 = 4.5716 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 68^9 = 3.1087 * 10^16 different passwords
  • If there are 10 characters, then we have 68^10 = 2.1139 * 10^18 different passwords
  • If there are 11 characters, then we have 68^11 = 1.4375 * 10^20 different passwords
  • If there are 12 characters, then we have 68^12 = 9.7748 * 10^21 different passwords

Adding up those subtotals gives

68^8+68^9+68^10+68^11+68^12 = 9.9207 * 10^21

different passwords possible.

<h3>Answer: Approximately 9.9207 * 10^21 </h3>

======================================================

Part b)

Let's find the number of passwords where we don't have a special symbol

There are 52+10 = 62 different characters to pick from

  • If there are 8 characters for this password, then we have 62^8 = 2.1834 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 62^9 = 1.3537 * 10^16 different passwords
  • If there are 10 characters, then we have 62^10 = 8.3930 * 10^17 different passwords
  • If there are 11 characters, then we have 62^11 = 5.2037 * 10^19 different passwords
  • If there are 12 characters, then we have 62^12 = 3.2263 * 10^21 different passwords

Adding those subtotals gives

62^8+62^9+62^10+62^11+62^12 = 3.2792 * 10^21

different passwords where we do not have a special character. Subtract this from the answer in part a) above

( 9.9207 * 10^21)  - (3.2792 * 10^21) = 6.6415 * 10^21

which represents the number of passwords where we have one or more character that is a special symbol. I'm using the idea that we either have a password with no symbols, or we have a password with at least one symbol. Adding up those two cases leads to the total number of passwords possible.

<h3>Answer: Approximately 6.6415 * 10^21</h3>

======================================================

Part c)

The answer from part a) was roughly 9.9207 * 10^21

It will take about 9.9207 * 10^21  nanoseconds to try every possible password from part a).

Divide 9.9207 * 10^21  over 1*10^9 to convert to seconds

(9.9207 * 10^21 )/(1*10^9) = 9,920,700,000,000

This number is 9.9 trillion roughly.

It will take about 9.9 trillion seconds to try every password, if you try a password per second.

------

To convert to hours, divide by 3600 and you should get

(9,920,700,000,000)/3600 = 2,755,750,000

So it will take about 2,755,750,000 hours to try all the passwords.

------

Divide by 24 to convert to days

(2,755,750,000)/24= 114,822,916.666667

which rounds to 114,822,917

So it will take roughly 114,822,917 days to try all the passwords.

------

Then divide that over 365 to convert to years

314,583.334246576

which rounds to 314,583

It will take roughly 314,583 years to try all the passwords

------------------------------

<h3>Answers:</h3>
  • 9.9 trillion seconds
  • 2,755,750,000 hours
  • 114,822,917 days
  • 314,583 years

All values are approximate, and are roughly equivalent to one another.

5 0
3 years ago
Other questions:
  • Which statement is true regarding the graph?
    9·1 answer
  • How do you solve 5+y=7
    11·2 answers
  • If 14y - 4 = 24y + 26 , then 12y =
    15·2 answers
  • What angles do perpendicular lines form
    9·1 answer
  • Find the surface area.<br> 11 in<br> 9 in
    12·1 answer
  • Please help with #14 don’t need the graph just the variables 4 the total cost please!!!?!?!?!?
    5·1 answer
  • Three of four numbers have a sum of 22. If the average of the four numbers is 8, what is the fourth number ?
    8·1 answer
  • Can someone please help me with and explain this?
    10·1 answer
  • 1. how many cubic meters are in 250,000 cubic centimeters?
    12·1 answer
  • . <br> Find the value of x for which ABCD must be a parallelogram.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!