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Mamont248 [21]
1 year ago
12

The sampling distribution for a goodness of fit test is the a. Poisson distribution b. t distribution c. normal distribution d.

chi-square distribution
Mathematics
1 answer:
Dmitriy789 [7]1 year ago
5 0

The chi-square distribution serves as the sampling distribution for the goodness of fit test since it quantifies how well the distribution derived from the data fits the empirical distribution.

<h3>What is sampling distribution?</h3>

The sampling distribution is the probability distribution of a statistic that is obtained by repeated sampling of a certain population. The mean or mode of a population's mean or mode of a variable is one example of the many different choices for a statistic that are described in this passage. The sampling distribution of a proportion is obtained by repeating your survey or poll for each possible sample of the population. For instance, instead of asking 1,000 cat owners what cat food they prefer, you could conduct a number of polls.

To know more about sampling distribution,

brainly.com/question/29375938

#SPJ4

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What is the probability that two people chosen at random were born on the same day of the week? b)What is the probability that i
zaharov [31]

Answer:

See explanation below

Step-by-step explanation:

First, in order to solve this, we need to use the expression to calculate the probability of these events to happen.

The first is conditional probability which is:

P(B|A) = P(AUB)/P(A)

The second would be the complemental rule of probability which is:

P(E) = 1 - P(e)

With these two expressions, let's calculate the probability for each part:

a) A week has 7 days, and for the first person, he has 7 options to be born, so probability of that person is:

P(1st person) = 7/7 = 1

Now, the second person also has the same options than person 1, but the condition here is that he has to match the same day of person 1, so, he only has 1 option out of 7 to be the same day so:

P(A|B) = 1/7

Finally the probability would be:

P = 1 * 1/7 = 1/7 or 0.143

b) In this part, we have a n group of selected random people. Let's use logic here, if we choose more than 8 persons randomly, we know that 2 of them has born on the same day at least. (Think about it, 7 days a week, 7 persons born in different days, but if you add one, that person born one day that another person in the previous group born too), so probability that when n is >7, is 1.

To know that at least 2 person born on the same day of the week, we have to choose a number of 7 people at least. From that number and below, we can calculate the probability. To do this shorter, I will do for n = 7 and n = 6.

By complemental rule, we know that:

P(born on same day) = 1 - P(not born on same day)

The probability of not born on the same day would be n - 1/n° days

For n = 7

We have 7 ways of choosing the first person, 6 ways to choose the seconds, then 5 ways to choose the following and so on....

P = 1 - 7/7 * 6/7 * 5/7 * 4/7 * 3/7 * 2/7 * 1/7 = 0.994

Doing the same thing with n = 6

P = 1 - 7/7 * 6/7 * 5/7 * 4/7 * 3/7 * 2/7 = 0.957

We can do this with n = 5 through n = 3, and you will get the other results if you need to show that.

n = 5

P = 1 - 7/7 * 6/7 * 5/7 * 4/7 * 3/7 = 0.85

n = 4

P = 1 - 7/7 * 6/7 * 5/7 * 4/7 = 0.65

n = 3

P = 7/7 * 6/7 * 5/7 = 0.388

c) As you can see, in the part b) when the value of n is 4 or higher, you'll get a probability greater than 1/2 (0.5), so we need to choose at least 4 people at random.

c)

7 0
3 years ago
∠BEC is formed inside a circle by two intersecting chords. If minor arc BD = 94 and minor arc CA = 166, what is the measure of
igor_vitrenko [27]
The complete question is
<span>∠BEC is formed inside a circle by two intersecting chords. If minor arc BD = 94 and minor arc CA = 166, what is the measure of ∠ BEC?

the picture in the attached figure

we know that
The angle formed inside of a circle by two intersecting chords is </span><span>the half-summit of the arcs that comprise it and its opposite.
so
</span>∠BED=(1/2)*[arc AC+arc BD]-----> (1/2)*[166+94]-----> 130°
∠BEC+∠BED=180°-----> by supplementary angles
∠BEC=180-130-----> 50°
<span>
the answer is
</span>∠BEC=50°<span>

</span>

4 0
3 years ago
Find the exact value of s in the given interval that has the given circular function value.
docker41 [41]

Answer:

\displaystyle s=\frac{3\pi}{4}

Step-by-step explanation:

<u>Trigonometric Values</u>

We need to find the angle s in the interval [π/2,π] where:

\displaystyle \sin s=\frac{\sqrt{2}}{2}

There are two possible angles that have the same sine value in the first rotation of s. Any angle on the first quadrant has the same sine as its supplementary angle in the second quadrant.

The first angle s whose sine is \frac{\sqrt{2}}{2} is:

\displaystyle s=\frac{\pi }{4}

The other angle is its supplementary angle:

\displaystyle s=\pi-\frac{\pi }{4}=\frac{3\pi}{4}

Only this last angle lies on the required interval, thus:

\boxed{\displaystyle s=\frac{3\pi}{4}}

8 0
3 years ago
An article measured speeds of vehicles on several roads in the state of Kansas. On South Cedar Niles, 73 vehicles were observed,
shutvik [7]

Answer:

The p- value is 0.2996.

Step-by-step explanation:

This is a right-tailed test.

The null and alternative hypothesis is

H_0:p=0.60\\H_a:p>0.60

Point estimate = sample proportion=\hat{P}=x/n=0.630

Test statistics

$z=\left(\hat{p}-p_{0}\right) / \sqrt{p}_{0^{*}}\left(1-p_{0)} / n\right.$\\$=(0.630-0.60) / \sqrt{(0.60 * 0.40) / 73}$\\$=0.526$\\P-value $=P(Z>z)$\\$=0.2996$\\The $\mathrm{P}$ -value is $0.2996$

6 0
3 years ago
How much force would it take for a 1000 kg car that is travelling at 30 m/s to come to a stop within 3 seconds?
Vlada [557]

Answer:

About 200% force

Step-by-step explanation:

8 0
3 years ago
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