Finding the Bearing<span> of a </span>Ship<span>
Example : A </span>ship<span> leaves the port of Miami with a </span>bearing<span> of S80◦E and a </span>speed<span> of. 15 knots. After 1 hour, the </span>ship<span> turns 90◦ toward the south.</span>
I will solve one for you to get you a idea so next u can solve all
To know whether line is tangent toa circle or not we should know that that line is a tangent line of a circle if it intersects circle at single point.
and this will always be perpendicular at radius
so in problem
1)
diameter is given 7.5
and u can see they make a right triangle ABC if that is perpendicular so segment AB is tangent to a circle.
Lets see by applying <span>Pythagorean Theorem
</span>this is method we can say that this is in fact a right triangle
a^2=b^2=c^2
a,b are shorter side c is longer side
(7.5)^2+(8)^2=(17)^2
56.25+64=289
120.25=289
both are not equal so they are not forming right triangle so segment AB is not a tangent line.
x=3/2-1/4
8x+2y=12
move the variable to the right side and change the sign.
8x=12-2y
divide both sides of the equation by 8
x=3/2-1/4y
the final solution is
x=3/2-1/4y
−3b+2.5=4
Subtract 2.5 from both sides.
−3b+2.5−2.5=4−2.5
−3b=1.5
Divide both sides by -3.
−3b/−3 = 1.5/−3
b=−0.5
It should be A if I did the math right which I think I did
