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3 years ago

Yea.....can sum1 help pls

Mathematics

2 answers:

vichka [17]3 years ago

8 0

Answer:

208

Step-by-step explanation:

8*8=64

9*8/2=36

36*4=144

144+64=208

have a nice day :)

Bingel [31]3 years ago

6 0

Your answers 208 just took the test

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maw [93]

Answer:

£930

Step-by-step explanation:

Put the numbers in the formula and do the arithmetic. The annual earnings are expected to be 12 times the monthly earnings.

T = 0.2(12×£1375 -11850) = 0.2(£16500 -11850) = 0.2(£4650)

T = £930

The caterer will pay £930 in income tax for the year.

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3 years ago

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Part A- Which could be the total number of solutions to the system of equations?

Sladkaya [172]

A) No solutions

B) It's because the question gives you that both lines have the same slope. Remember that having the same slope makes the two lines parallel, which means they'll never intersect.

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3 years ago

Can someone help me find the slope

Serggg [28]

Answer:

I believe the answer is C, -4/5.

Step-by-step explanation:

You first find two points on the line and substitute them into the slope formula. I used points (-10,10) and (5,-2).

1. $y_2-y_1/x_2 - x_1$

2. -2-10/5-(-10)

3. -12/15

4. -4/5

I hope this helps, sorry for the late response.

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3 years ago

hours 0-4 (section A) the person is traveling away from their starting location. how far do they travel in those 4 hours ? remem

tangare [24]

Answer:

Step-by-step explanation:

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3 years ago

Find two positive numbers whose difference is 30 and whose product is 2584.

kvasek [131]

Answer:

$38$ and $68$ .

Step-by-step explanation:

Let $x$ be the smaller one of the two number.

$x$ must be a positive integer. The other number would be $(x + 30)$ .

The question states that the product of the two numbers is $2584$ . In other words:

$x\, (x + 30) = 2584$ .

Rearrange this equation and solve for $x$ :

$x^{2} + 30\, x - 2584 = 0$ .

The first root of this quadratic equation would be:

$\begin{aligned}x_{1} &= \frac{(-30) + \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= \frac{(-30) + \sqrt{900 + 10336}}{2} \\ &= \frac{(-30) + \sqrt{11236}}{2} \\ &= \frac{(-30)}{2} + \sqrt{\frac{11236}{2^{2}}} \\ &= (-15) + \sqrt{2809} \\ &= (-15) + 53 \\ &= 38 \end{aligned}$ .

Similarly, the second root of this quadratic equation would be:

$\begin{aligned}x_{1} &= \frac{(-30) - \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= (-15) - 53 \\ &= -68\end{aligned}$ .

Since the question requires that both numbers should be positive, $x > 0$ . Therefore, only $x = 38$ is valid.

Hence, the two numbers would be $38$ and $(38 + 30)$ , which is $68$ .

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3 years ago

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