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3 years ago

Write and graph an equation in two variables that shows the relationship between the time and the distance.

Mathematics

1 answer:

cluponka [151]3 years ago

7 0

Answer:

The relation between the time and the distance will be:

y = 15x

The graph of the equation y = 15x is attached below.

Step-by-step explanation:

We know that the equation of linear function in two variables in the slope-intercept form is

y = mx+b

where

m is the rate of change or slope

b is the y-intercept

Let y be the distance

Let t be the time

Given that the object moves 15 meters in 1 second.

Thus, the rate of change or slope = m = 15

As there is no initial condition in our case.

Thus the y-intercept b = 0

Now, substituting m = 15 and b = 0 in the linear function

y = mx+b

y = 15x + 0

y = 15x

Therefore, the relation between the time and the distance will be:

y = 15x

The graph of the equation y = 15x is attached below.

Examples:

Calculate the distance in 1 second

put x = 1 in the equation

y = 15(1) = 15 meters

Calculate the distance in 10 second

put x = 10 in the equation

y = 15(10) = 150 meters

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Consider the function f(x)= x² - 4

Arisa [49]

Answer:

(X+2) (X-2) . This is the final answer

Step-by-step explanation:

Solving f(x) = x^2 - 4

A^2 - B^2 is a special case where the original equation before it was foiled is

(A + B) (A - B) because the middle terms will cancel out when foiled.

This means that the equation can be written as

(X + 2)(X - 2) = 0

Each of these you will then set equal to 0 and then solve

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I hope this helps you! let me now if its right ok <3 :)

4 0

3 years ago

On a map, 9 cm represents 15 miles. If the distance between two cities on the map is 15 cm, how many miles separate the cities?

torisob [31]

Answer:

15 cm on the map is equal to 25 miles.

Step-by-step explanation:

Given that,

On a map, 9 cm represents 15 miles.

The distance between two cities is 15 cm. We need to find the distance in miles.

9 cm = 15 miles

$1\ cm=\dfrac{15}{9}\ \miles$

So, 15 cm is equal to,

$15\ cm=\dfrac{15}{9}\times 15\ miles\\\\=25\ miles$

So, 15 cm on the map is equal to 25 miles.

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3 years ago

-74 + 36.2=<br> Step by step

My name is Ann [436]

Step-by-step explanation:

-74+36.2=-37.8

I hope it will help you

3 0

3 years ago

Read 2 more answers

Show all steps!!!

Lunna [17]

$-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3$
$\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}$
$\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}$
$=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}$
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4 0

3 years ago

what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible

zheka24 [161]

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

$\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$

$=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}$

The quotient when $\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}$ in simplified form is $\frac{-(x+1)}{(x-1)(x+3)}$

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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2 years ago