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Sholpan [36]
3 years ago
9

David rode his bicycle for 6 hours and jogged for 8 hours during the

Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0
72 hours I hope this helps
slega [8]3 years ago
4 0

Answer:

72 hours

Step-by-step explanation:

Because if he bikes 54 then he will need to do 8 x 9 = 72 because if he biked 54 hours then he did 6 x 9 = 54 so the answer is 72 hours (u multiply by 9) hope this helps

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Step-by-step explanation:

a = 5b-10

a+b = 26

(5b-10)+b = 26

b = 6

a= 5b + 10 = 40

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3 years ago
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100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
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