the problem is a pattern that multiplies by two and subtracts one each time.
3x2=6 6-1=5 5x2=10 10-2=9 9x2=18 18-1=17 17x2=34 34-1=33
Answer and step-by-step explanation:
We learn that (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
So in this case, it would be:
= x^3 + (3*x^2*2) + (3*x*2^2) + 2^3
= x^3 + 6x^2 + 3x * 4 + 8
= x^3 + 6x^2 + 12x + 8
This is the standard form of the equation
Hope it help you :3
True is the answer of the day
X-intercepts: (1,0), (3,0)
Y-intercepts: (-6,0)
