On the planet Jupiter, a ball this thrown upward at a velocity at 10m/s. It's height, h(t) meters after t seconds is given by th
e equation h(t)=-12.5(t-0.4)^2+4.
a) what is the maximum height the ball reaches?
b) what was the height of the ball when it was released from the throwers hand?
c) how many seconds after the ball was hit and did it land on the surface of Jupiter to the nearest second?
1 answer:
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Step-by-step explanation:
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