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Sergio039 [100]
3 years ago
12

The half-life of carbon-14 is 5,730 years. How many grams of parent material will remain from a 120-gram sample of carbon-14 aft

er 2 half-lives?
90

60

30

15
Mathematics
2 answers:
Oduvanchick [21]3 years ago
4 0
After one half-life . . . 1/2 of the total parent material

After another half-life . . . 1/2 of the half remains = 1/4 of the total original parent

If the original parent is 120 grams, then (1/4 x 20) = <u><em>30 grams</em></u> remains
after 2 half-lives.  It makes no difference what the substance is, or
how long its half-life is.
alex41 [277]3 years ago
3 0
t_{\frac{1}{2}}=5730\\&#10;N_0=120\ g\\&#10;t=2t_{\frac{1}{2}}=2\cdot5730=11460\\&#10;N(t)=?\\\\&#10;N(t)=N_0\left(\frac{1}{2}\right)^{\frac{t}{t_{\frac{1}{2}}}}\\&#10;N(11460)=120\cdot\left(\frac{1}{2}\right)^{\frac{11460}{5730}}\\&#10;N(11460)=120\cdot\left(\frac{1}{2}\right)^2\\&#10;N(11460)=120\cdot\frac{1}{4}\\&#10;N(11460)=30\ g
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Find the x- and y-intercepts of the following equation:<br> 2x+3y=-24
Ilya [14]

Answer:

Algebra 

 Topics 

How do you find the intercepts of x2y−x2+4y=0?

Algebra  Graphs of Linear Equations and Functions  Intercepts by Substitution

2 Answers

Gió

Mar 24, 2015

For the intercepts you set alternately x=0 and y=0 in your function:

and graphically:

Answer link

Alan P.

Mar 24, 2015

On the X-axis y=0

So

x2y−x2+4y=0

becomes

x2(0)−x2+4(0)=0

→−x2=0

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On the Y-axis x=0

and the original equation

x2y−x2+4y=0

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(0)2y−(0)2+4y=0

→y=0

The only intercept for the given equation occurs at (0,0)

Answer link

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2 years ago
Please help me with this please
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9. Is the line through points P(7, 3) and Q(11, 0) perpendicular to the line through points R(6, –3) and S(3, 1)? Explain.A)Yes;
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