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3 years ago

A 19 = 548 and a 33 = 968 Find a 27

Mathematics

1 answer:

s2008m [1.1K]3 years ago

4 0

Answer:

The value of a₂₇ is 788

Step-by-step explanation:

a₁₉ = 548

a₃₃ = 968

Now,

a₁₉ = 548 can be written as

a + 18d = 548 ...(1) and

a₃₃ = 968 can be written as

a + 32d = 968 ...(2)

Now, from equation (2) we get,

a + 32d = 968

a + 18d + 14d = 968

548 + 14d = 968 (.°. <u>a + 18d = 548</u>)

14d = 968 - 548

14d = 420

d = 420 ÷ 14

d = 30

Now, for the value of a put the value of d = 30 in equation (1)

a + 18d = 548

a + 18(30) = 548

a + 540 = 548

a = 548 - 540

a = 8

Now, For a₂₇

a₂₇ = a + 26d

a₂₇ = 8 + 26(30)

a₂₇ = 8 + 780

a₂₇ = 788

Thus, The value of a₂₇ is 788

<u>-TheUnknownScientist</u>

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A farmer has 184 sheep. 23% are ewes. How many rams does have?

Ludmilka [50]

The correct answer is 142

number of sheep= 184

ewe= 23% of total sheep

= 23/100 × 184

= 42 approximately

if number of ewe = 42

Then number of ram= ( total number of sheep - number of ewe)

= 184- 42

= 142 approximately

Therefore, number of of ram is 142

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3 years ago

2 and 3/8 minus 1/4 times 1/8

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Answer:

2 11/32 or 75/32

Step-by-step explanation:

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4 years ago

The ranger of the function x2+2x-8is allá

allsm [11]

Answer:

$\mathrm{Range\:of\:}x^2+2x-8:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-9\:\\ \:\mathrm{Interval\:Notation:}&\:[-9,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

As the function is

$x^{2} +2x-8$

As we know that domain is the set of input values for which the function is defined.

Therefore,

$\mathrm{Domain\:of\:}\:x^2+2x-8\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

And range is defined as:

The set of the dependent variable for which the function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(-1,\:-9\right)$

$f\left(x\right)\ge \:-9$

Therefore,

$\mathrm{Range\:of\:}x^2+2x-8:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-9\:\\ \:\mathrm{Interval\:Notation:}&\:[-9,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Keywords: graph, domain, range

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