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2 years ago

15

The length of one side of APTV is given. Use the relationship between the sides of a 30°-60°-90° triangle to find the lengths of

the other two sides.

1 answer:

aliina [53]2 years ago

8 0

Answer:

your answers will be 3 and 6

Step-by-step explanation:

have a nice day !!^_^

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1. A student invests $500 in a savings account that earns 4% interest per

bixtya [17]

Answer:

The equation can be used to determine the amount of money S(t) that her savings account has after t years is $S(t)=500(1.04)^t$

Step-by-step explanation:

A student invests $500 in a savings account

Principal = $500

Rate of interest = 4% = 0.04

We are supposed to find equation can be used to determine the amount of money S(t) that her savings account has after t years

Formula : $A=P(1+r)^t$

Where A is the amount after t years =S(t)

t = time

r = rate of interest in decimals =0.04

P = Principal=500

Substitute the value in the formula :

So, $S(t)=500(1+0.04)^t$

$S(t)=500(1.04)^t$

Hence The equation can be used to determine the amount of money S(t) that her savings account has after t years is $S(t)=500(1.04)^t$

6 0

2 years ago

solong [7]

The answer is D). 125 = 1.28f. This accounts for both sales tax and the cost of food.

3 0

2 years ago

HELP Use either law of sines or law of cosine. Need help on this problem! show work please!

Marina86 [1]

Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

sin(Q)/13 = sin(85)/19

sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

Q = 42.9693397461 ... or ... Q = 137.0306602539

These values are approximate.

----------------

Now if Q = 42.9693397461 approximately, then angle P is

P = 180-Q-R

P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

P = 180-Q-R

P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

sin(P)/QR = sin(R)/PQ

sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

4 0

2 years ago

Read 2 more answers

solve systems of equation. equation number 1: 9 x squared + 4 y squared equals 144. equation 2: x squared plus y squared equals

grigory [225]

$9x^{2} + 4y^{2} =144$
$x^{2} + y^{2}=24$

$9x^{2} + 4y^{2} =144$
$4x^{2} + 4y^{2}=96$
by the difference
5 $x^{2}$ =48
so x= $\sqrt{\frac{48}{5}}$ or x=- $\sqrt{\frac{48}{5}}$
and $y^{2}$ =24- $\frac{48}{5}$
then y= $\sqrt{\frac{72}{5}}$ or - $\sqrt{\frac{48}{5}}$

5 0

2 years ago

The length of a phone conversation is normally distributed with a mean of 4 minutes and a standard deviation of 0.6 minutes. Wha

Arlecino [84]

The z-score for 5 minutes is found from:
$z=\frac{X-\mu}{\sigma}
$
$z=\frac{5-4}{0.6}=1.667$
Reference to a normal distribution table shows that the cumulative probability for a z-score of 1.667 is around 0.9522.
Therefore the probability that a conversation lasts for longer than 5 minutes is:
1 - 0.9522 = 0.048 to 3 d.p.

8 0

3 years ago

Read 2 more answers