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qaws [65]
3 years ago
13

Will mark Brainlest, if you answer fast!!!

Mathematics
2 answers:
noname [10]3 years ago
8 0

Answer:

-2x

Step-by-step explanation:

Zanzabum3 years ago
7 0
-2x
Dvrjebdjbsbsbdksbsisgsjbsoegehehdgshdvhegdhejsjshshs
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A regular decagon has 10 sides. How many reflectional symmetries does a regular decagon have?
lina2011 [118]

The rule for regular polygons are very easy. The number of reflectional symmetries is same as the number of sides. Regular polygons have all sides the same length and all angles same. Reflection symmetry means that you can fold the shape along that line and it will match up.

For this question, we want the number of reflectional symmetries of a regular decagon. Decagon is a 10 sided figure. Hence, the number of reflectional symmetries is 10.

There are 5 symmetry lines from one vertex to opposite vertex and 5 more symmetry lines form midpoint of one side to midpoint of opposite side.

ANSWER: 10

7 0
3 years ago
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Please help me answer this thank you
nexus9112 [7]
Scale for y - 1:1
Scale for x - 1:10

Reason- so that i can plot the points on the graph without any modification to the given one.

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What is 238 divided by 3 with remainders?
saul85 [17]
238 can be divided by 3, 79 times with a remainder of 3

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A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c
Alenkinab [10]

Answer:

C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

l\times b\times h

where l is the length, b is the base and h is the height.

Volume of box =

s^2h = 150\\\\h = \dfrac{150}{s^2}

Area of base =

\text{side}\times \text{side} = s^2

Cost of concrete for the base = $4

Cost of base($) = 4s^2

Area of roof =

\text{side}\times \text{side} = s^2

Cost of material for the roof = $2

Cost of roof ($) = 2s^2

Area of 4 walls =

4\times (sh)\\=4sh

Cost of material for the side = $2.50

Cost of material of side($) =

2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}

is the required cost function.

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3 years ago
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