Answer:the nth term of the sequence, Tn= -3n +12
Step-by-step explanation:
The nth term of an arithmetic progression is given as
Tn= a+ (n-1) d
where a= first term
and d = common difference
In this sequence, 9, 6 ,3 ,0, -3, -6 we can see that the number is decreasing by 3
The first term, a= 9
and common difference, d = -3
using our formulae
Tn= a+ (n-1) d
Tn= 9 + ( n-1) -3
Tn=9- 3n+ 3
Tn= -3n +12
Answer:
the last one : 8/4 < 5/2
Step-by-step explanation:
C. A function can only have one y value for an x value
Let x represent the number of students in Janelle’s group.
If Janelle brings 3 markers for each person in her group, then she brings 3x markers for x students. You also know that she brings <span>5 extra markers for everyone to share. Thus, the total amount of markers she brings is 3x+5.
</span>
If Janelle brings in 23 markers in all, then the equation <span><span>3x+5=23 </span> represaents the mathematical model. </span>
3x=23-5,3x=18,x=6
Answer: there are 6 students in Janelle's group.
Step-by-step answer:
Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals
Ra = 2Fcos(a) ..............................(1)
Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals
Rb = 2Fcos(b)..............................(2)
We are given that
Ra = 2Rb ....................................(3)
Substitute (1) & (2) in (3) gives
2Fcos(a) = 2(2Fcos(b))
Expand
2Fcos(a) = 4Fcos(b)
Simplify
cos(a) = 2 cos(b) QED
Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.
Have a nice day!
