What is the modulus of z = 3 - 4i? z =
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[surface area of the composite solid]=1*(4*6)+2*(4*4)+2*(4*6)+2*(4*√13/2)+2*(6*2√2/2)
[surface area of the composite solid]=24+32+48+4√13+12√2
[<span>surface area of the composite solid]=135.39 yd</span>²
the answer is
135.39 yd²
[surface area of the composite solid]=1*(4*6)+2*(4*4)+2*(4*6)+2*(4*√13/2)+2*(6*2√2/2)
[surface area of the composite solid]=24+32+48+4√13+12√2
[<span>surface area of the composite solid]=135.39 yd</span>²
the answer is
135.39 yd²
Hope this helps
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