Answer:
glasses of milk=4
quatar pounds servings of meat =5
two slices of whole grains bread =8
Step-by-step explanation:
Let m= milk
r=meat
b=bread
0.1m+3.4r+2.2b=35 (1)
8.5m+22r+10b=224 (2)
m+20r+12b=200 (3)
Multiply (1) by 85 and (2) by 1
8.5m+289r+187b=2,975 (4)
8.5m+22r+10b=224 (5)
Subtract (5) from (4)
267r+177b=2,751 (6)
Recall,
8.5m+22r+10b=224 (2)
m+20r+12b=200 (3)
Multiply (2) by 1 and (3) by 8.5
8.5m+22r+10b=224 (7)
8.5m+170r+102b=1700 (8)
Subtract (7) from (8)
148r+92b=1,476 (9)
Recall,
267r+177b=2,751 (6) and
148r+92b=1,476 (9)
Multiply (6) by 148 and (9) by 267
26196b=407,148 (10)
24564b=394,092 (11)
Subtract (11) from (10)
1,632b=13,056
Divide both sides by 1,632
b=13,056/1,632
b=8
Substitute the value of b in (9)
148r+92b=1,476 (9)
148r+92(8)=1,476
148r+736=1,476
148r=1,476-736
148r=740
Divide both sides by 148
r=740/148
r= 5
Substitute the value of b and r in (1)
0.1m+3.4r+2.2b=35 (1)
0.1m+3.4(5)+2.2(8)=35
0.1m+17+17.6=35
0.1m+34.6=35
0.1m=35-34.6
0.1m=0.4
Divide both sides by 0.1
m=0.4/0.1
m=4
4 glasses of milk, 5 quatar pounds servings of meat and 8 two slices of whole grains bread will supply the required nutrients.
Answer:
The mean of the combined group is 76.67 ≈ 77
Step-by-step explanation:
- The sum of the grades in Tom's group is 20×70 = 1400
- The sum of grades in Alice's group is 10×90=900
- The sum of gradees in the combined group is =1400+900=2300
- Then the mean grade of the combined group is

where
- 2300 is the sum of the all grades in the combined group
- 30 is the total number of people in the group
Answer:
eight people drink 6 glasses of water
Step-by-step explanation:
Answer:
the rate of change of the water depth when the water depth is 10 ft is; 
Step-by-step explanation:
Given that:
the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.
We are meant to find the rate of change of the water depth when the water depth is 10 ft.
The diagrammatic expression below clearly interprets the question.
From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t
Then the similar triangles ΔOCD and ΔOAB is as follows:
( similar triangle property)


h = 2.5r

The volume of the water in the tank is represented by the equation:



The rate of change of the water depth is :

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec
Then,

Therefore,

the rate of change of the water at depth h = 10 ft is:




Thus, the rate of change of the water depth when the water depth is 10 ft is; 
36:39 in simplest form is 12:13