I believe it is A. Sorry if it’s wrong <3
Y' = 2x/(x^2 -3) y'(2) = 4
Using the point slope equation:
y-0 = 4(x-2)
y = 4x - 8
Answer:
Step-by-step explanation:
Work done is given by
, where d = length of cable and w = weight of cable.
Here, d = 175 ft and w = 3 lb/ft
Now, 
![work \ done= 3\left [175x-\frac{x^2}{2} \right ]_0^{175}](https://tex.z-dn.net/?f=work%20%5C%20done%3D%203%5Cleft%20%5B175x-%5Cfrac%7Bx%5E2%7D%7B2%7D%20%20%5Cright%20%5D_0%5E%7B175%7D)
![work \ done= 3\left [175^2-\frac{175^2}{2} \right ]](https://tex.z-dn.net/?f=work%20%5C%20done%3D%203%5Cleft%20%5B175%5E2-%5Cfrac%7B175%5E2%7D%7B2%7D%20%20%5Cright%20%5D)
Answer:
BE = FC = 3 inches, EF = 2 inches
Step-by-step explanation:
The sum of angles A and D is 180°, so the sum of their half-angles is 90°. That is, half of A plus half of B add to 90°, so the bisector from B intersects AE at a right angle. Call that point of intersection X.
Then angle ABX = angle EBX, so triangle ABX is congruent to triangle EBX. Sides AB and BE are corresponding sides of congruent triangles.
The same argument applies to sides DC and CF.
Thus we have BE = CF = 3 inches, and EF is the left-over distance, 2 inches.
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