The probability that a student chose football given that they like watching sports is: c. 0.27.
<h3>
Conditional Probability</h3>
Using this formula
P[Like (Football)/Like (Sport)]
Where:
P=Probability
Like (Football)=0.23
Like (Sport)=0.23+0.18+0.26+0.17=0.84
Let plug in the formula
P[Like (Football)/Like (Sport)]=0.23/0.84
P[Like (Football)/Like (Sport)]=0.27
Therefore the probability that a student chose football given that they like watching sports is: c. 0.27.
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Answer:
its a negative correlation and a traingle the a nd c are farther apart then the m and n
Step-by-step explanation:
1) slope-2/3, y-intercept-(0,6)
2) slope- -2/3, y-intercept-(0,-3)
3) slope- 8, y-intercept-(0,-6)
4) slope- 6, y-intercept-(0,-8)
A is the answer
divide 0.5/ 0.1
Step-by-step explanation:
1.
123445+(89-23765)=99769
2.
234.57+(5.23-2.678)=237.122
3
(21.54+ 80.27)-68.501=33.309