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3 years ago

Which side lengths form a right triangle?

Mathematics

1 answer:

deff fn [24]3 years ago

8 0

Answer:

Step-by-step explanation:

6^2+8^2=100

sqrt of 100 = 10 so it would form a right triangle

You might be interested in

How to Simplify. (–21 × 3) + (15 ÷ –3)

vladimir2022 [97]

Answer:

-68 is your answer

Step-by-step explanation:

Remember to follow PEMDAS (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction)

First, solve each parenthesis

(-21 x 3) = -63

(15/-3) = -5

Next, add

(-63) + (-5) = -63 - 5 = -68

-68 is your answer

5 0

3 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago

Consider U = {x\x is a real number}

zysi [14]

Answer:

The fourth pair of statement is true.

9∈A, and 9∈B.

Step-by-step explanation:

Given that,

U={x| x is real number}

A={x| x∈ U and x+2>10}

B={x| x∈ U and 2x>10}

5 ∈ A , 5 ∈ B

If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.

Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.

So, 5∉A, and 5∉B.

6 ∈ A , 6 ∈ B

If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.

Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.

So, 6∉A, and 6∈B.

8 ∈ A , 8 ∈ B

If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.

Similarly, If 8∈ B, Then it will be satisfies 2x>10. 2.8=16>10.

So, 8∉A, and 8∈B.

9 ∈ A , 9 ∈ B

If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.

Similarly, If 9∈ B, Then it will be satisfies 2x>10. 2.9=18>10.

So, 9∈A, and 9∈B.

3 0

3 years ago

Sally went to the clearance rack at a department store and found a shirt she wanted to buy. The shirt was $36.00 and is on sale

jeka57 [31]

Answer:

33.34%.

Step-by-step explanation:

Given that,

The actual price of the shirt = $36

Price on sale = $24

We need to find the percent of the decrease. The formula for the percentage is given by :

$\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100$

Putting all the values,

$\%=\dfrac{24-36}{36}\times 100\\\\=33.34\%$

So, the percentage decrease in the price of the shirt is 33.34%.

6 0

3 years ago

A 12- ounce bag of birdseed cost $3.12. A 16-ounce bag of birdseed cost $3.84. Which is the better deal. How much money do you s

OlgaM077 [116]

Answer:

16oz bag, $0.32 saved

Step-by-step explanation:

3.12/12 = 0.26

3.84/16 = 0.24

For the 12-ounce bag, it would be $0.26 per ounce. For the 16-ounce bag, it would only be $0.24 per ounce.

16*0.26=4.16

4.16 - 3.84 = 0.32

$0.38 saved

6 0

3 years ago