If i remember correctly i think you just cross multiply <span />
Answer:
Let's say Raj's height is 60 inches
60-3 = H
H= Howard's height
60 = Raj's height
Or it could be with two variables
R-3 = H
R = Raj's height
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line


once you get the slope and solve for "y", that'd be the equation of the line.
It’s already in ascending order.
3/5= .6
5/8= .625
5/6= .833
7/4= 1.75