First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23
Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer:
All angles in a rectangle are congruent, because in a rectangle, all angles are 90 degrees.
Answer:
B
x is the price of the sweater so 3x and add $15 for the skirt which would add up to $90
4 - 5x = 2x + 25
4 = 7x + 25
-21 = 7x
-3 = x
4 - 5x + 2x + 25 = ac
4 - 5(-3) + 2(-3) + 25 = ac
4 - (-15) + (-6) + 25 = ac
19 + (-6) + 25 = ac
38 = ac
