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3 years ago

Pls help me with my math

Mathematics

1 answer:

Svetach [21]3 years ago

8 0

Answer:

the last one.

let me know if you need an explanation.

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question 31 pts a fair six-sided die is tossed 300 times. find the expected value of the sample mean of the values obtained in t

mojhsa [17]

The expected value of the sample mean of the values obtained in these 300 tosses is 3.5

Given :

A fair six sided die is tossed 300 times

We have to find the expected value of the sample mean of the values obtained in these 300 tosses.

A dice have six sides:

In a fair dice every side has equal chance of occurrence,

Now the probability of presence of each side = 1/6

Now the expected value of the sample mean of the values obtained in these 300 tosses is given by:

E(x) = Σx P(x =x)

= 1*1/6 + 2*1/6 + 3*1/6 + 4*1/6 + 5*1/6 + 6*1/6

= 1/6 + 2/6 + 3/6 + 4/6 + 5/6 + 6/6

= 1/6 (1+2+3+4+5+6)

= 1/6 (21)

= 21/6

E(x) = 3.5

Hence, the expected value of the sample mean of the values obtained in these 300 tosses is 3.5

To know more about sample mean check the below link:

brainly.com/question/29739571

#SPJ4

3 0

2 years ago

What is the volume of a sphere that has a diameter of 36 yd?

Katen [24]

Volume=(4/3)pi(r^3)

radius=1/2diameter
d=36
radius=1/2 36
radius=18

subsitute
volume=4/3 pi 18^3
volume=4/3 pi 5832
volume=23328/3 pi
volume=7776pi

aprox pi to 3.14
volume=7776 times 3.14
volume=24416.64

answer is 24416.64 yd^3

8 0

4 years ago

What is 100,897,567×25

Afina-wow [57]

It equals to 2,522,439,175.

3 0

4 years ago

Read 2 more answers

In a test of the effectiveness of garlic for lowering cholesterol, 8181 subjects were treated with raw garlic. Cholesterol leve

xz_007 [3.2K]

Answer:

With garlic treatment, the mean change in LDL cholesterol is not greater than 0.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired t-test is used to determine the effectiveness of garlic for lowering cholesterol.

A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.

The hypothesis for the test can be defined as follows:

H₀: With garlic treatment, the mean change in LDL cholesterol is not greater than 0, i.e. d ≤ 0.

Hₐ: With garlic treatment, the mean change in LDL cholesterol is greater than 0, i.e. d > 0.

The information provided is:

$\bar d=0.40\\SD_{d}=16.2\\\alpha =0.01$

Compute the test statistic value as follows:

$t=\frac{\bar d}{SD_{d}/\sqrt{n}}\\\\=\frac{0.40}{16.2/\sqrt{81}}\\\\=0.22$

The test statistic value is 0.22.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

$p-value=P(t_{n-1}>0.22)\\=P(t_{80}>0.22)\\=0.4132$

*Use a t-table.

The p-value of the test is 0.4132.

p-value= 0.4132 > α = 0.01

The null hypothesis was failed to be rejected.

Thus, it can be concluded that with garlic treatment, the mean change in LDL cholesterol is not greater than 0.

3 0

3 years ago

PLEASE HELP NOW what is 9 - 4x^3 + 2x^2 + 8x^3 + 1 + 6x^2 simplified??

gulaghasi [49]

Don’t click the links. Don’t trust it

7 0

3 years ago

Read 2 more answers