Ask question

Ask question

All categories

3 years ago

9

Hello! if i could have help on this question it would be nice, having some trouble :)

1 answer:

Nookie1986 [14]3 years ago

4 0

Answer:

12

Step-by-step explanation:

He would have to work 12 weekends at $25. 25x11+220=$520

You might be interested in

Three semicircles are placed in a rectangle, as shown below. The length of the rectangle is 30 m . Find the area of the shaded r

Anuta_ua [19.1K]

Answer:

The area of the shaded region is: 32.25m^2

Step-by-step explanation:

Given

See attachment for rectangle and semicircles

Required

The shaded region

We have:

$l =30$ --- length of the rectangle

This means that the diameters of the three circles add up to 30m.

So, the diameter of 1 is:

$d = l/3$

$d = 30/3$

$d = 10$

The area of one circle is:

$A_1 = \pi * \frac{d^2}{8}$

$A_1 = 3.14 * \frac{10^2}{8}$

$A_1 = 3.14 * \frac{100}{8}$

$A_1 = 39.25m^2$

The area of the three circles is:

$A_2 = 3 * A_1$

$A_2 = 3 *39.25m^2$

$A_2 = 117.75m^2$

The area of the rectangle is:

$A_3 = 30 * r$

Where r is the radius of the circle

And

$r =d/2$

$r =10/2$

$r =5$

So, we have:

$A_3 = 30 * r$

$A_3 = 30 * 5$

$A_3 = 150$

So, the shaded region is:

$A_4 = A_3 - A_2$

$A_4 = 150 - 117.75$

$A_4 = 32.25m^2$

8 0

3 years ago

Evaluate 7m+ 3mn when m=8 and n=14?Answers:aA:84,B:196,C:392,D=168

Aleksandr-060686 [28]

Answer:

c) 392

Step-by-step explanation:

4 0

4 years ago

Sqrtx^2+6x+9 if x≥3<br><br><br><br> please help quick idk how to do this at all

katrin [286]

Answer:

x+3

Step-by-step explanation:

sqrt(x^2+6x+9)

factor

We know this is a perfect square trinomial

sqrt(( x+3)^2)

Taking the square root of a square

x+3

7 0

3 years ago

Perform the indicated operation and express the result as a simplified complex number. I need help with 35

skelet666 [1.2K]

Given:-

$\frac{3+4i}{2-i}$

To find:-

The simplified form.

At first we take conjucate and multiply below and above.

The conjucate is,

$2+i$

So now we multiply. we get,

$\frac{3+4i}{2-i}\times\frac{2+i}{2+i}$

Now we simplify. so we get,

$\frac{3+4i}{2-i}\times\frac{2+i}{2+i}=\frac{6+3i+8i+4(i)^2}{2^2-i^2}$

We know the value of,

$i^2=-1$

Substituting the value -1. we get,

$\begin{gathered} \frac{6+3i+8i+4(i)^2}{2^2-i^2}=\frac{6+3i+8i+4(-1)_{}^{}}{2^2-(-1)^{}} \\ \text{ =}\frac{6-4+11i}{2+1} \\ \text{ =}\frac{2+11i}{3} \end{gathered}$

So now we split the term to bring it into the form a+ib. so we get,

$\frac{2+11i}{3}=\frac{2}{3}+i\frac{11}{3}$

So the required solution is,

$\frac{2}{3}+i\frac{11}{3}$

3 0

1 year ago

At the end of a snow storm, Adam saw there was a lot of snow on his front lawn. The

Artyom0805 [142]

Answer:

544

Step-by-step explanation:

First of all you do 3x5 divided by 65x65+BTS-BLP Then you add the 544 that was the answer then you get 3 add that by dora then you get your answer 544 :D

6 0

3 years ago