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How do you solve linear equations using substitution
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Assuming that the given expression is 
You calculate dy / dx = y' as:
1
-------. y' = e^(x/y) * (-x/y^2)
x + y
=> y' = e^(x/y) * (-x/y^2) * (x + y).
Answer dy / dx = - e^(x/y) (x/y^2) (x+y)
You calculate dy / dx = y' as:
1
-------. y' = e^(x/y) * (-x/y^2)
x + y
=> y' = e^(x/y) * (-x/y^2) * (x + y).
Answer dy / dx = - e^(x/y) (x/y^2) (x+y)