0.0215 has ____ significant figures

2 answers:

8 0

3.

When counting significant figures, ignore the 0s that show up before a number more than 0.

If, for example, a number is 0.03067, then there are 4 significant figures, because the first two 0s are ignored but the 0 after 3 is counted!

Sorry if my explanation is difficult to comprehend haha. Please do ask if you’re still unsure

shepuryov [24]2 years ago

7 0

Answer:

has 3 significant figures

Step-by-step explanation:

because zeros are counted if they are between the numbers

You might be interested in

Consider the table showing the given, predicted and residual values for a data set.

nadezda [96]

Hi friend,
D) (4, 0.1)
Hope this helps you!

4 0

3 years ago

Read 2 more answers

Simplify the following radical Sqrt 126x^13

fenix001 [56]

Answer:

$\large\boxed{\sqrt{126x^{13}}=3x^6\sqrt{14x}}$

Step-by-step explanation:

$Domain:\ x\geq0\\\\\sqrt{126x^{13}}=\sqrt{9\cdot14\cdot x^{12+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{9\cdot14\cdot x^{12}\cdot x^1}=\sqrt{9\cdot14\cdot x^{6\cdot2}\cdot x}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\ \text{and}\ (a^n)^m=a^{nm}\\\\=\sqrt9\cdot\sqrt{14}\cdot\sqrt{(x^6)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=3\cdot\sqrt{14}\cdot x^6\cdot\sqrt{x}=3x^6\sqrt{14x}$