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storchak [24]
4 years ago
10

What is the product of x+5 and x^2+3x-4 ? (write your answer in standard form) Show all work please!

Mathematics
1 answer:
rusak2 [61]4 years ago
6 0
(x+5)*(x^2+3x-4) = x^3+8x^2+11x-20
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If the circle below is cut from the square of plywood below, how many square inches of plywood would be left over? Use π = 3.14,
Elis [28]

Answer:

86in²

Step-by-step explanation:

Find the complete question attached

Area of the circle = πr²

Area of the square = L²

Length of the side of the square

r is the radius of the circle

r = L/2 = 20/2 =10in

Given

Length of the side of the circle = 20in

Area of the square = 20²

Area of the square = 400in²

Area of the circle =π(10)²

Area of the circle = 3.14(100)

Area of the circle= 314in²

Amount of plywood left over = 400in²-314in² = 86in²

8 0
3 years ago
{(−1, 5), (2, 8), (5, 3), (13, −4)} what are the range
makkiz [27]
(x;\ y)\\\\(-1, \fbox5), (2, \fbox8), (5, \fbox3), (13, \fbox{-4})\\\\\boxed{The\ range:y\in\{-4;\ 3;\ 5;\ 8\}}
7 0
4 years ago
Find f (-2) if f (x)=4x+1
telo118 [61]

Answer:

f(-2)=4(-2)+1= 7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help soon! Thanks! Solve for x
spin [16.1K]

Answer:

x=27\degree

Step-by-step explanation:

\because AC || DE.... (given)

\therefore m\angle CAD= m\angle EDF\\ (corresponding \: \angle s)

\therefore m\angle BAD= m\angle EDF\\(\because B\in \overleftrightarrow{AC})

\therefore m\angle BAD= 2x\\(\because m\angle EDF=2x)

In\:\triangle BAD,

m\angle BAD+m\angle BDA+m\angle ABD= 180\degree

2x+2x+72\degree = 180\degree

4x= 180\degree -72\degree

4x= 108\degree

x= \frac {108\degree}{4}

x=27\degree

5 0
3 years ago
For the rhombus below, find the measure of angles 1,2,3 and 4.
Alexus [3.1K]

Answer:

∠1 is 33°

∠2 is 57°

∠3 is 57°

∠4 is 33°

Step-by-step explanation:

First off, we already know that ∠2 is 57° because of alternate interior angles.

Second, it's important to know that rhombus' diagonals bisect each other; meaning they form 90° angles in the intersection. Another cool thing is that the diagonals bisect the existing angles in the rhombus. Therefore, 57° is just half of something.

Then, you basically just do some other pain-in-the-butt things after.

Since that ∠2 is just the bisected half from one existing angle, that means that ∠3 is just the other half; meaning that ∠3 is 57°, as well.

Next is to just find the missing angle ∠1. Since we already know ∠3 is 57°, we can just add that to the 90° that the diagonals formed at the intersection.

57° + 90° = 147°

180° - 147° = 33°

∠1 is 33°

Finally, since that ∠4 is just an alternate interior angle of ∠1, ∠4 is 33°, too.

5 0
3 years ago
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