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Sunny_sXe [5.5K]
3 years ago
8

Select all of the factors of x3 + 5x2 + 2x – 8.

Mathematics
2 answers:
Nikolay [14]3 years ago
5 0

Answer:

i think it would be multiplied by x

Step-by-step explanation:

that sounds like the best thing to do

MaRussiya [10]3 years ago
4 0

Answer: (x+4), (x-1), (x+2) or C,D,F

Step-by-step explanation:

Edge = (x + 4)(x + 2)(x - 1)

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Triangles 1 and 2 have the angle measures
lawyer [7]

Answer:

C

Step-by-step explanation:

Both triangles have three angles of the same value.

Remember that the angles in all triangles add up to 180°.

Let's use that to find out the unknown angles.

For the first triangle:

180 - 82 - 43 = 55°

55° is also in the second triangle.

Let's check with the second triangle:

180 - 82 - 55 = 43°

43° is also in the first triangle.

Therefore, both triangles are similar as the angles in both triangles are the same - 82°, 43° and 55°.

Hence, C.

7 0
3 years ago
Solve the inequality and graph the solution set on a number line. Express the solution set in both​ set-builder and interval not
shusha [124]
<span>-8 < x -3 < 1
we have two inequations: 
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
*  x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun
8 0
3 years ago
How to solve by completing the square: -X2 +1190X-3200
Vlad [161]

Answer:

x2+6512

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
What is the prime factorization for 147
NemiM [27]
Prime Factorization = Divide by factors that are prime number

147 ÷  3 = 49
49 ÷ 7 = 7
7 ÷ 7 = 1
 
147 = 3 x 7 x 7

147 = 3 x 7²

-------------------------------------------------------------------------------
Answer: 147 = 3 x 7²
-------------------------------------------------------------------------------
4 0
3 years ago
Read 2 more answers
What's twenty and fifteen thousandths in standard form HELP PLSSSSS
xeze [42]
20.015

Because there are 3 numbers before a thousand so 3 numbers behind the decimal are the thousandths.
4 0
3 years ago
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