We have been given that
Now, we need to find an ordered pair that must be on the graph of
On substituting x=0 in the above equation, we get
Therefore, the required ordered pair is given by (0,-1)
Answer:
5 squares will be painted black.
Step-by-step explanation:
There are 9 squares, and 4 of them will be painted white, so that means that the remaining squares will be painted black. 9-4=5, so 5 squares will be painted black.
Hope this helped! :)
Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
