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Assoli18 [71]
3 years ago
13

Pls somebody that knows this answer it please

Mathematics
2 answers:
hoa [83]3 years ago
5 0
For the first one the answer is 96. I think the answer for the second one is B and for the third question the answer is c. Hope this helps!
Yuliya22 [10]3 years ago
3 0

Answer:

Im pretty sure it is 48 but it could be 96

Step-by-step explanation:

I just found the area and halved that.

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borishaifa [10]

a^(4-2) b^(3-5)

Answer =a^2b^-2

8 0
3 years ago
HELP PLEASE WITH MATH
kifflom [539]
14)NO..... -2x+5y=10.....-2(-3)+5(2)=10.....6+10 is not =10
15)YES......-2x+5y=10....-2(-10)+5(-2)=10.....20-10=10
16)YES......-2x+5y=10.....-2(5)+5(4)=10......-10+20=10
3 0
3 years ago
Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y
Drupady [299]

Answer:

V = \frac{\pi^2}{8}

V = 1.23245

Step-by-step explanation:

Given

y = \cos 2x

y = 0; x = 0; x = \frac{\pi}{4}

Required

Determine the volume of the solid generated

Using the disk method approach, we have:

V = \pi \int\limits^a_b {R(x)^2} \, dx

Where

y = R(x) = \cos 2x

a = \frac{\pi}{4}; b =0

So:

V = \pi \int\limits^a_b {R(x)^2} \, dx

Where

y = R(x) = \cos 2x

a = \frac{\pi}{4}; b =0

So:

V = \pi \int\limits^a_b {R(x)^2} \, dx

V = \pi \int\limits^{\frac{\pi}{4}}_0 {(\cos 2x)^2} \, dx

V = \pi \int\limits^{\frac{\pi}{4}}_0 {\cos^2 (2x)} \, dx

Apply the following half angle trigonometry identity;

\cos^2(x) = \frac{1}{2}[1 + \cos(2x)]

So, we have:

\cos^2(2x) = \frac{1}{2}[1 + \cos(2*2x)]

\cos^2(2x) = \frac{1}{2}[1 + \cos(4x)]

Open bracket

\cos^2(2x) = \frac{1}{2} + \frac{1}{2}\cos(4x)

So, we have:

V = \pi \int\limits^{\frac{\pi}{4}}_0 {\cos^2 (2x)} \, dx

V = \pi \int\limits^{\frac{\pi}{4}}_0 {[\frac{1}{2} + \frac{1}{2}\cos(4x)]} \, dx

Integrate

V = \pi [\frac{x}{2} + \frac{1}{8}\sin(4x)]\limits^{\frac{\pi}{4}}_0

Expand

V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [\frac{0}{2} + \frac{1}{8}\sin(4*0)])

V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [0 + 0])

V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})])

V = \pi ([{\frac{\pi}{8} + \frac{1}{8}\sin(\pi)])

\sin \pi = 0

So:

V = \pi ([{\frac{\pi}{8} + \frac{1}{8}*0])

V = \pi *[{\frac{\pi}{8}]

V = \frac{\pi^2}{8}

or

V = \frac{3.14^2}{8}

V = 1.23245

4 0
3 years ago
100 is 19% of what number?
larisa [96]

Answer: 526.32

Formula: 100 x 100 / 19

8 0
4 years ago
How do you find the missing dimension of a triangle
ki77a [65]

Answer:

The Pythagorean theorem states that a2 + b2 = c2 in a right triangle where c is the longest side. You can use this equation to figure out the length of one side if you have the lengths of the other two.

4 0
3 years ago
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