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3 years ago

Band kids let's talk

Mathematics

2 answers:

vivado [14]3 years ago

7 0

Answer:

Yessssssssssssssssssssss

Step-by-step explanation:

Illusion [34]3 years ago

3 0

Answer:

Trumbone noises*

Step-by-step explanation:

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Two out of every 5 jelly beans in a bag are green.

patriot [66]

Answer:

54 are green

Step-by-step explanation:

2/5 are green

We have 135 jelly beans

2/5 * 135

54 are green

7 0

3 years ago

Read 2 more answers

Multiply and simplify (2x-3)(x^2+4x-6)

mars1129 [50]

Answer: 2x^3 + 5x^2 - 24x + 18

Step-by-step explanation:

4 0

3 years ago

What is the answer to the system of equations problem 3x=2y+10 9y=3x-7

Gemiola [76]

Solving:

$\left \{ {{3x = 2y + 10} \atop {9y = 3x-7}} \right.$
Organize by putting the unknowns left and right the numbers without letter, changing the signal when changing sides.
 $\left \{ {{3x-2y=10\:(I)} \atop {-3x+9y=-7\:(II)}} \right.$
Eliminate opposites (+ 3x and -3x)
 $\left \{ {{\diagup\!\!\!\!3x-2y=10} \atop {-\diagup\!\!\!\!3x+9y=-7}} \right.$
$\left \{ {{-2y=10} \atop {9y=-7}} \right.$
----------------------------
$7y = 3$
$\boxed{y = \frac{3}{7} }$

Now substitute the found value "y" in the first equation:
 $3x-2y=10\:(I)$
$3x-2* \frac{3}{7} =10$
$3x- \frac{6}{7} = 10$
$\frac{21x}{\diagup\!\!\!\!7} - \frac{6}{\diagup\!\!\!\!7} = \frac{70}{\diagup\!\!\!\!7}$
$21x - 6 = 70$
$21x = 70 + 6$
$21x = 76$
$\boxed{x = \frac{76}{21} }$

Answer:
$(x,y) = ( \frac{76}{21} , \frac{3}{7} )\end{array}}\qquad\quad\checkmark$


Taking the truth proof

$3x - 2y = 10\:(I)$
$3* \frac{76}{21} - 2* \frac{3}{7} = 10$
$\frac{228}{21} - \frac{6}{7} = 10$
$\frac{1596-126}{147} = 10$
$\frac{1470}{147} = 10$
$10 = 10\:(TRUE)$

8 0

3 years ago

7x+3y=8 6x-3y=5 what is the value of x-y? PLEASE HELP & FAST!

Brut [27]

X=7
y= -9

hope this helps

3 0

3 years ago

Question 8 (4 points) Find the values of x and y if NO = x + 2y, MO = 3x, PQ = 6x + 4, and OQ = 2y + 4.

kirill [66]

Answer:

x = 12 and y = 16

Step-by-step explanation:

Given the following lengths;

NO = x + 2y,

MO = 3x,

PQ = 6x + 4, and

OQ = 2y + 4.

The following postulates are true;

MN = PQ

Since MO + ON = MN

MN = 3x + x+2y

MN = 4x + 2y

Recall that PQ = 6x+4

Equating both expressions;

4x + 2y= 6x+4

Collect like terms;

4x-6x + 2y = 4

-2x + 2y = 4

x - y = -4 ...... 1

Also MO = OQ

3x = 2y + 4

3x-2y= 4 ....2

from 1; x = -4 + y

Substitute into 2:

3x-2y= 4

3(-4+y)-2y = 4

-12+3y-2y = 4

-12+y = 4

y = 4 + 12

y = 16

Since x = -4+y

x = -4 + 16

x = 12

Hence x = 12 and y = 16

5 0

3 years ago