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ludmilkaskok [199]
2 years ago
9

Is there a limit to the number of 0s that can be added to a dividend when dividing decimals?

Mathematics
1 answer:
Makovka662 [10]2 years ago
6 0

Answer:

no

Step-by-step explanation:

you can use as many 0s as you need to

hope this helps!

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Point A is located at (−214,14). Point B is located at (234,14). What is the distance between point A and point B?
Sunny_sXe [5.5K]

Answer:

10, 14

Step-by-step explanation:

take the x values and plug into mid point formula and then divide by 2

so... (-214 + 234) divided by 2 = 10

do the same for the y values

so ... (14 + 14) divided by 2 = 14

so ... 10,14

7 0
2 years ago
Read 2 more answers
Given line t passes through (0,-5) and (-1,3) and liner passes through (-4,3) and (4,2).
kupik [55]

Answer:

neither

Step-by-step explanation:

Slope of the first line: (y2 -y1)/(x2-x1) = (3-(-5)/-1 = 8/-1 = -8

Slope of the second line: (2-3)/4-(-4) = -1/8

They are neither parallel nor perpendicular. In fact the two lines have different slope so they can’t be parallel. In addition the product of their slope is not -1, so they can’t be perpendicular,

3 0
3 years ago
Asapppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!
svp [43]

Answer: x = 148 degrees

Step-by-step explanation:

This problem makes use of Supplementary Angles.  Supplementary Angles states that two angles that make up a line add to 180.  Thus, simply use the equation 32 + x = 180

x = 148

Hope it helps <3

5 0
3 years ago
Darren wants to estimate the mean age in a population of trees. He'll sample nnn trees and build a 90\%90%90, percent confidence
Alchen [17]

Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In this problem, we have that the parameters are given as follows:

M = 3, z = 1.645, \sigma = 16.

Hence, solving for n, we find the sample size.

M = z\frac{\sigma}{\sqrt{n}}

3 = 1.645\frac{16}{\sqrt{n}}

3\sqrt{n} = 1.645 \times 16

\sqrt{n} = \frac{1.645 \times 16}{3}

(\sqrt{n})^2 = \left(\frac{1.645 \times 16}{3}\right)^2

n = 76.97

Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
Simplify ratio 5cm to 10m​
miskamm [114]

Answer:

1 : 2

Step-by-step explanation:

5 cm : 10 cm ← divide each part by 5 cm

= 1 : 2

3 0
3 years ago
Read 2 more answers
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