Answer:
A (2) =4*2 +882
Step-by-step explanation:
Assuming we have parallel lines, we can solve for x.
Since a = 3x - 10 (vertically opposite angles are equal),
3x - 10 = 2x + 15 (alternate angles are equal)
x = 25
Hence, angle a = 3(25) - 10 = 65°
Answer:
In a quadratic equation of the shape:
y = a*x^2 + b*x + c
we hate that the discriminant is equal to:
D = b^2 - 4*a*c
This thing appears in the Bhaskara's formula for the roots of the quadratic equation:

You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)
If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)
If D > 0 we have two different roots, so the graph touches the x-axis in two different points.
A. The distance between the red ant and the black ant is five units.
To represent the red ant,
xr = 3 - t
yr = 2 + 2 t
zr = 6 + 2 t
To represent the black ant,
xb = t/2
yb = 2 + 3 t
zb = 2 + t
To calculate,
at t = 0
xb - xr = -3
yb - yr - 2-2 = 0
zb - zr = 2-6 = -4
Therefore,
d = √(9+16) = √(25) = 5
b. There will be no collision between the two ants.
To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2
If t = 2,
2 + 2*2 = 2 + 3*2