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KiRa [710]
2 years ago
9

Divide 2/3 by 5 2/15 7 1/2 3/10 3 1/3

Mathematics
1 answer:
Zinaida [17]2 years ago
6 0
7.5 is the answer for this questio
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PLEASE HELP!! WILL MARK BRAINLIEST AND HELP YOU!!!
bearhunter [10]

given: s is the midpoint of rt

definition of midpoint: rs st

given: st xg

transitive property of congruence: rs xy

5 0
3 years ago
Select two fractions that can be rewritten with a denominator of 24
vagabundo [1.1K]
2/12 and 3/8 Hope it's right YAYYYYY
3 0
3 years ago
Olivia wrapped a string around a circle and found it was 30 mm long. Approximately, what is the radius of this circle
mafiozo [28]

Answer:7.5

Step-by-step explanation: cause I looked it up lol

8 0
3 years ago
Given that El bisects ZCEA, which statements must be
Alexxx [7]

Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.

(See attachment below for the figure)

m∠CEA = 90°

m∠CEF = m∠CEA + m∠BEF

m∠CEB = 2(m∠CEA)

∠CEF is a straight angle.

∠AEF is a right angle.

Answer:

m∠CEA = 90°

∠CEF is a straight angle.

∠AEF is a right angle

Step-by-step explanation:

Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.

Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.

Thus, the three statements that must be TRUE are:

m∠CEA = 90°

∠CEF is a straight angle.

∠AEF is a right angle

3 0
3 years ago
Cual es la derivada de ()=√x sin
fgiga [73]

Answer:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

Step-by-step explanation:

We assume that the function of interest is:

f(x) =\sqrt{x} sin (x)

And on this case we can use the product rule for a derivate given by:

\frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)

Where f(x) =\sqrt{x} and g(x) =sin (x)

And replacing we have this:

f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)

3 0
3 years ago
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