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Ipatiy [6.2K]
3 years ago
15

How to price that line segment CD bisects line segment AB.

Mathematics
1 answer:
Schach [20]3 years ago
8 0
The congruence of the 2 triangles can be proved, angle C is common , CD is common, CA = CB, THEN the 2 triangles are congruent, the 2 triangles are equal so AD = DB hence CD bisects AB.

AND just that a attitude does not divides a line into equal half's, in an obtuse angle triangle the altitude is outside, only the median can divide a line into 2 equal half's or a triangle

hope this helps if this did Pls like and have any doubts ask me in the comments section, feel free
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Simplify this equation 9−4d≥−3
Snezhnost [94]

Answer:

d ≤3

Step-by-step explanation:

9−4d≥−3

Subtract 9 from each side

9-9−4d≥−3-9

−4d≥−12

Divide by -4, remembering to flip the inequality

-4d/-4 ≤-12/-4

d ≤3

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3 years ago
38 is is 10 times as much as
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38 is 10 times more than 3.8
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Find the original price of a pair of shoes if the sale price is $144 after a 25% discount.
k0ka [10]

Answer:

$192

Step-by-step explanation:

1: Subtract the discount from 100% then divide the sale price by this number (100%-25%=75%, $144/75%=$192)

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4 0
3 years ago
Read 2 more answers
Simplify. (−5p4z6u)3
sineoko [7]
The rules of exponents tell you that you can distribute the exponent to each of the factors. When one already has an exponent, those exponents multiply.
(-5p^{4}z^{6}u)^{3}=(-5)^{3}\cdot(p^{4})^{3}\cdot(z^{6})^{3}\cdot u^{3}\\\\=-125p^{4\cdot 3}z^{6\cdot 3}u^{3}\\\\=-125p^{12}z^{18}u^{3}
4 0
3 years ago
You work with the office of city planning which is currently evaluating a new contract for a major highway. The chosen contracto
Ipatiy [6.2K]

Answer:

0.5488 = 54.88% probability that there are no defects in the completed highway.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

The portion of highway that your city is building is 30 miles long.

The mean is one defect per 50 miles. Since the highway is 30 miles, we have that:

\mu = \frac{30}{50} = 0.6

What is the probability that there are no (0) defects in the completed highway?

This is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.6}*0.6^{0}}{(0)!} = 0.5488

0.5488 = 54.88% probability that there are no defects in the completed highway.

7 0
3 years ago
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