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Anuta_ua [19.1K]

3 years ago

12

Find the area of the composite figure. Please help me!!

1 answer:

elena55 [62]3 years ago

5 0

Answer:

1,824 sq inches

Step-by-step explanation:

area of rectangle: 48 x 32 = 1536

area of triangle: (48 x 12) / 2 = 288

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The frequency table shows the results of drawing 20 cards from a bag of 100. There are an

zepelin [54]

Answer:

It's 50 percent right

Step-by-step explanation:

there are many colors and they could all be different

4 0

4 years ago

Carmen has a rope 54 feet long. She wants to cut it into 6-foot lengths to make jump ropes for the members of the jump roping te

Ilia_Sergeevich [38]

54 divided by 6 is 9. she can 9 times

7 0

4 years ago

Read 2 more answers

Can someone please help I really need these points

spayn [35]

Given:

Two chords intersect each other inside the circle.

To find:

The value of x.

Solution:

According to intersecting chords theorem, if two chords intersect each other inside the circle, then the product of two segments of one chord is equal to the product of two segments of second chord.

In the given circle,

$AE\times CE=BE\times DE$

$(3x-11)\times (5x-4)=(x+2)\times (-x+17)$

$15x^2-12x-55x+44=-x^2+17x-2x+34$

$15x^2-67x+44+x^2-15x-34=0$

$16x^2-82x+10=0$

Divide both sides by 2.

$8x^2-41x+5=0$

Splitting the middle term, we get

$8x^2-40x-x+5=0$

$8x(x-5)-1(x-5)=0$

$(8x-1)(x-5)=0$

Using zero product property, we get

$(8x-1)=0$ or $(x-5)=0$

$x=\dfrac{1}{8}$ or $x=5$

For $x=\dfrac{1}{8}$ , the side AE is negative. So, $x=\dfrac{1}{8}$ is not possible.

Therefore, the required solution is $x=5$ .

6 0

3 years ago

If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=4/5 and cos b=5

vladimir1956 [14]

First let's find the angles a and b.

We have then:
sin a = 4/5
a = Asin (4/5)
a = 53.13 degrees.

cos b = 5/13
b = Acos5 / 13
b = 67.38 degrees.

We now calculate cos (a + b). To do this, we replace the previously found values:
cos ((53.13) + (67.38)) = - 0.507688738
Answer:
-0.507688738
Note: there is another way to solve the problem using trigonometric identities.

4 0

3 years ago

Read 2 more answers

PLEASE HELP! THANK YOU!!!

Ronch [10]

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$3(x - 2) = 12$

$x = 6$

_________________________________

$6(x + 5) = 54$

$x = 4$

_________________________________

$3x + 5 = 32$

$x = 9$

_________________________________

$5(x + 7) = 45$

$x = 2$

_________________________________

$7x + 6 = 41$

$x = 5$

_________________________________

$2(x + 7) = 29$

$x = 7.5$

_________________________________

$4(x + 3) = 30$

$x = 4.5$

_________________________________

$5(x - 4) = 20$

$x = 8$

_________________________________

$3x - 10 = 23$

$x = 11$

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7 0

3 years ago

Read 2 more answers